Answer:
D. Drawing 50 names from a hat containing the names of every student in the school.
(3y^7)^3 3^3*y^(7*3)
------------ = ------------------
9y^9 9*y^9
(3y^7)^3 3^3*y^(7*3) 27*y^21 (mult. together the exponents 3 and 7)
------------ = ------------------ = --------------
9y^9 9*y^9 9*y^9
That 27/9 reduces to 3. y^(21) / y^9 reduces to y^12.
Thus, we obtain 3*y^12 (answer)
Please do the next one, asking questions if need be, and showing your work.
If Anne gave birth to four males and four females, and they all gave birth the same way again, they would have eight males, but if it were to happen again, there would be 12 males and 12 females in total if you don't count all of the females giving birth EACH to four males and four females. Otherwise it would be 40 males, and 40 females.
1a. Y = mx + b
Y = 2x + b
-2 = 2(5) + b
-2 = 10 + b, b = 12
Equation: y = 2x + 12
1b. Standard form: Ax + By = C
subtract 12 and y from both sides
2x - y = -12
Equation: 2x - y = -12
