Answer:
C
Step-by-step explanation:
You first distribute within the parentheses which is -(-z-2). This is going to make everything positive as everything in the parentheses is negative. You should get z+2. Next, you plug that back in. It should be-3z+z+2. You simplify to get -2z+2. Hope this helps!
Answer:
$112.75
Step-by-step explanation:
5% of 118.65=5.9
118.65-5.9=112.75
Step-by-step explanation:
Given the expression that modeled the relationship between these quantities (calories from grams of carbohydrate and the rest of the ingredients) as
4c+5 = 27
From the equation, the constant value of 5 represents the calories in grams of the rest of the ingredients present in the bite.
Let us calculate the value of c from the equation
4c+5 = 27
4c + 5- 5 = 27-5
4c = 22
c = 22/4
c = 5.5
This means that the total calories of carbohydrate the granola bite contains is 4(5.5) i.e 21 calories of carbohydrate
<em>Note that 8 cannot be the solution to the equation because for us to eliminate 5 from both sides of the equation, we need to subtract it from both sides not add. If 5 was added to both sides, the value of c would have been (32/4 i.e 8) which would have been wrong.</em>
Answer:
y = 14.5
Step-by-step explanation:
given that y varies directly as x
mathematically,
y ∝ x
y = kx .............................................. where k is the constant of proportionality.
k = y /x
given that
y = 79
x = 49
k = 79/49
k = 1.61
to find y when x = 9
from
y = kx
y = 1.61 × 9
y = 14.5
therefore the value of y when x = 9 in ths variation is evaluated to be equals to 14.5
Each sibling got 1 poster, 8 CDS and 72 books.
<h3>How the belongings were divided </h3>
Since the belongings were divided equally, each sibling would get the same amount of belongings. In order to determine the belongings each person got, we would divide each possession by 3.
- Number of poster each person got = 3/3 = 1
- Number of books each person got = 216
- Number of CDs each person got = 24 / 3 = 8
To learn more about division, please check: brainly.com/question/194007
