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Kruka [31]
4 years ago
7

Write a sistuatetion for 15x - 20 <130 and then solve

Mathematics
1 answer:
rodikova [14]4 years ago
7 0
X=9 beecause 135-20 =115 and 130 is bigger than 130
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Subtract.<br> (6-v-25) - (7+-4)
dmitriy555 [2]

Answer:

\left(6-v-25\right)-\left(7+\left(-4\right)\right)=-v-22

Step-by-step explanation:

Considering the expression

\left(6-v-25\right)\:-\:\left(7+-4\right)

\left(6-v-25\right)-\left(7+\left(-4\right)\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

6-v-25-\left(7-4\right)

\mathrm{Subtract\:the\:numbers:}\:7-4=3

6-v-25-3

\mathrm{Group\:like\:terms}

-v+6-25-3

\mathrm{Add/Subtract\:the\:numbers:}\:6-25-3=-22

-v-22

Therefore,

\left(6-v-25\right)-\left(7+\left(-4\right)\right)=-v-22

7 0
3 years ago
Que is on pic.i can't able to type in text.
ad-work [718]
It's not difficult to compute the values of A and B directly:

A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}
A=\tan^{-1}(\sin\theta)-\dfrac\pi4

B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt
B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}
B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2

Let's assume 0, so that |\csc\theta|=\csc\theta.

Now,

\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}
\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}
\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)
\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in A and B.
3 0
3 years ago
How do I find the missing values to .. (4,y) and (0,5) m = 3 over 4​
Aleks04 [339]

Answer:

(4,3) (4,5)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
List all sets that apply for 0.6
uranmaximum [27]

Answer:

i know

Step-by-step explanation:0.6

3 0
3 years ago
While looking at some reports, a store manager notes that sets of bunk beds that retail for
Anvisha [2.4K]
Should be 7.5% I have to add more words to this sentence to post it
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2 years ago
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