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algol13
3 years ago
15

I need to know the answer to this !! just read please

Mathematics
1 answer:
alexandr1967 [171]3 years ago
4 0
15 which I think is to the nearest tenths
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Given:
Masja [62]

Answer:

9

Step-by-step explanation:

By joining N to L, you will have a right angled triangle which is right angle at N. Then r^2+36=(3+x)^2. r=9/2. PQ=2r=9

8 0
3 years ago
Millie works 8 hours on Saturday and earns £6.50 an hour. Her bus fare to work costs £2.75 and she also spends £4.25 on her lunc
Nimfa-mama [501]
The answer is 7.50 ......
6 0
3 years ago
Does anyone know how to solve this because im very confused.
krek1111 [17]
The answer is 4












Explanation :
3 0
3 years ago
What is an equation of a line that passes through the point of (-8 2) and (-4,-3)
Alex_Xolod [135]

Answer:

<h2>y = -5/4x -8</h2>

Step-by-step explanation:

(-8,2)=(x_1 ,y_1)\\(-4 ,-3) = (x_2 ,y_2)\\\\\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\\ \\\frac{y-2}{x-(-8)}= \frac{-3-2}{-4-(-8)}\\  \\\frac{y-2}{x+8}= \frac{-5}{-4+8} \\ \\\\\frac{y-2}{x+8} = \frac{-5}{4}\\ \\Cross\:Multiply \\4(y-2) = -5(x+8)\\\\4y-8 =- 5x-40\\\\4y = -5x-40+8\\\\4y =- 5x-32\\\\\frac{4y}{4} = \frac{-5x}{4} + \frac{-32}{4} \\\\y = -\frac{5}{4}x-8

3 0
3 years ago
The ideal width of a safety belt strap for a certain automobile is 6 cm. The actual width can vary by at most 0.45 cm. Write an
OlgaM077 [116]

Answer:

|x-6|\le 0.45

x\in [5.55,6.45]

Step-by-step explanation:

<u>Absolute Value Inequality</u>

Assume the actual width of a safety belt strap for a certain automobile is x. We know the ideal width of the strap is 6 cm. This means the variation from the ideal width is x-6.

Note if x is less than 6, then the variation is negative. We usually don't care about the sign of the variation, just the number. That is why we need to use the absolute value function.

The variation (unsigned) from the ideal width is:

|x-6|

The question requires that the variation is at most 0.45 cm. That poses the inequality:

|x-6|\le 0.45

That is the range of acceptable widths. Let's now solve the inequality.

To solve an inequality for an absolute value less than a positive number N, we write:

-0.45\le x-6 \le 0.45

This is a double inequality than can be easily solved by adding 6 to all the sides.

-0.45+6\le x \le 0.45+6

Operating:

5.55\le x \le 6.45

That is the solution in inequality form. Expressing in interval form:

\boxed{x\in [5.55,6.45]}

3 0
4 years ago
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