16. The graph of the function

1 answer:

8 0

$\text{Hello there!}\\\\\text{Our original equation is: y = 4x + 1}\\\\\text{Our new equation must be translated 3 units up}\\\\\text{This means that we're going up on the y axis, meaning that our}\\\text{"beginning point" will change}\\\\\text{Our beginning point is 1, so just add 3 to it}\\\\1+3 = 4\\\\\text{Put 4 as your beginning point in the equation:}\\\\y=4x+4\\\\\boxed{\text{Answer: y = 4x + 4}}$

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<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B%203%20%3D%205" id="TexFormula1" title="2x^{2} + 3 = 5" alt="2x^{2} + 3 = 5"

sveta [45]

Answer:

x = 1

Step-by-step explanation:

2x^2 + 3 = 5
2x^2 = 5 - 3
2x^2 = 2
x^2 = 2/2
x = \| 1
x = 1

6 0

3 years ago

Find the permeter of a quadrilateral with vertices at C (2,4), D(1,1), E(5,0), and F(3,4). Round your answer to the nearest hund

denpristay [2]

Answer:

12.76

Step-by-step explanation:

This is much easier to solve if you draw it out on a graph. The perimeter is the sum of all the sides. I used the Pythagorean theorem to find the hypotenuse.

${a}^{2} + {b}^{2} = {c}^{2} \\ c = \sqrt{ {a}^{2} + {b}^{2} }$

$dc = \sqrt{ {3}^{2} + {1}^{2} } = \sqrt{10} \\ cf = 1 \\ fe = \sqrt{ {4}^{2} + {2}^{2} } = \sqrt{20} \\ de = \sqrt{ {1}^{2} + {4}^{2} } = \sqrt{17} \\ \sqrt{10} + 1 + \sqrt{20} + \sqrt{17} = 12.76$