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Sloan [31]
2 years ago
12

Can I pls get help on this question

Mathematics
1 answer:
ale4655 [162]2 years ago
4 0

Answer:

Yes

Step-by-step explanation:

I had this exact question.

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A satellite is in an approximately circular orbit 36,000 kilometers from Earth’s surface. The radius of Earth is about 6400 kilo
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The answer is 266,407.507 km

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3 years ago
Wind forms dunes through ___.
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Answer:<u><em> I think it would have to be c) Sublimation</em></u>

7 0
2 years ago
Solve for the Simplest form
tino4ka555 [31]
How to solve:

\frac{5}{6} - \frac{3}{8}

Write all numerators above the least common denominator which is 24 in this case.
\frac{20-9}{24}

Subtract the numbers
\frac{11}{24}

Alternate form: 0.458333

The final, simplified, fraction answer is: \frac{11}{24}

7 0
3 years ago
Read 2 more answers
Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm
GuDViN [60]
Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones). 

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

P(x \ \textless \  3) = P(x = 0) + P(x = 1) + P(x = 2)&#10;\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}&#10;\\&#10;\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}&#10;\\&#10;\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}&#10;\\ \indent \boxed{P(x \ \textless \  3) \approx 0.00951836732 }&#10;

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.


5 0
3 years ago
Can u help me out I odnt get it very well
Svetradugi [14.3K]
16,3,3

She wants an equal amount of lotion and hand soap, if you do 48 divided by 16 you get 3 and if you do 64 divided by 16 you get 4 so if she wants equal she can put 3 in each box. Finally if you do 48 divided by 3 you get 16 and if you divide 64 by 3 you get 21.3 if you want equal you must go with 16.

Hope this helps :)
7 0
2 years ago
Read 2 more answers
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