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nydimaria [60]
4 years ago
12

PLEASE HELP, algebra 1

Mathematics
1 answer:
Rama09 [41]4 years ago
5 0
If x = 10 and y = 2, 10 was divided by 5.

so if x = 40, divide it by 5 which will give us 8.

Option C) is your answer.
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SERIOUS ANSWERS ONLY WILL GIVE BRAINLIEST
tensa zangetsu [6.8K]

Hello,

Part A:

f(x)=4x^2+8x-5\\=4(x^2+2x)-5\\=4(x^2+2x+1-1)-5\\=4(x+1)^2-9\\=(2(x+1)-3)(2(x+1)+3)\\=(2x-1)(2x+5)\\x-intercepts\ are\ x=\frac{1}{2} \ and\ x=-\frac{5}{2} \\

Part B:

x² coefficient is 4 >0 thus a minimun

as y=4(x+1)²-9 : vertex is (-1,-9)

Proof: see picture

Sorry for Part c: I don't know

In France, we make an array of (x,f(x)) and then plot the severals points.

4 0
3 years ago
Suppose Q-Mart plans to obtain information on a randomly selected sample of customers using each type of charge card, using equa
lesya [120]

Answer:

Independent

Step-by-step explanation:

Paired: Two different variable observed on same group at different points in time. Here a randomly selected samples is observed for type of change card.

Independent: A single variable observed on multiple groups.

6 0
4 years ago
Can you help me on question 13?!
koban [17]

Answer:B

Step-by-step explanation: 0.4 × 0.4 = 0.16 not much more explanation than that really

5 0
3 years ago
There are four highlights in the paragraph that show equations or phrases
aivan3 [116]

A reflection across the line y=0 (AKA the x-axis)

and then across the line x=0 (AKA the y-axis)

is the same as a rotation of 180º

clockwise about the origin because the lines intersect at the origin and at a 90º angle.

While all of that is true, you could also be more general, because reflecting over any two lines that intersect at the origin will result in a rotation about the origin and have an angle of rotation equal to twice that of the acute angle formed between the intersecting lines.

4 0
3 years ago
The diagram shows 5cm×5cm×5cm cube calculate the length of the diagonal ab
mario62 [17]

Answer:

AB = 5\sqrt{3} cm

Step-by-step explanation:

As we can see from the figure, BCDE is a square with each corner equal to 90°.

So that, BDE is a right triangle with corner BED equal to 90°

As BDE is a right triangle, according to Pythagoras theorem, we have:

         BD^{2} = BE^{2} +ED^{2} = 5^{2} + 5^{2} = 25 + 25 = 50cm

As the diagram s the cube, so that it can be seen that AD is perpendicular to the surface BCDE

=> AD is perpendicular to BD

=> ADB is the right triangle with corner ADB equal to 90°.

As ADB is the right triangle, ccording to Pythagoras theorem, we have:

AB^{2} =AD^{2} + BD^{2} = 5^{2} +50 = 25 +50 = 75 cm

=> AB = \sqrt{75}  = 5\sqrt{3} cm

Conclusion: AB = 5\sqrt{3}cm

4 0
3 years ago
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