For the answer to the question above, since the triangle is isosceles, the two legs have equal length. The coordinates of two vertices are given
P(3,3)
Q(3,1)
Assuming that PQ and QR are the legs of equal length, the distance between Q and R must be the same as the distance between P and Q
d = √[(3-3)² + (3-1)²
d = 2
Therefore, the coordinates of P is
(5,1)
the square of b: b^3
three fourths the square of b: (3/4)b^2
7 less than three fourths the square of b: (3/4)b^2 - 7
The factors of 50a³ are 1, 2, 5, 10, 25, 50,
and their products with a, a² and a³ .
The factors of 10a² are 1, 2, 5, 10,
and their products with 'a' and a² .
Their common factors are 1, 2, 5, 10,
and their products with 'a' and a².
Their greatest common factor is 10a² .
(Another way to spot it, easily, is to remember this helpful factoid:
If the smaller number is a factor of the larger number,
then the smaller number is their greatest common factor.
Using the greatest common factor, then . . .
50a³ + 10a² = 10a²(5a + 1) .
Answer:
1-5
Step-by-step explanation:
I be leave it is the 3rd one.
