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3 years ago

14

SERIOUS ANSWERS ONLY WILL GIVE BRAINLIEST

1 answer:

tensa zangetsu [6.8K]3 years ago

4 0

Hello,

Part A:

$f(x)=4x^2+8x-5\\=4(x^2+2x)-5\\=4(x^2+2x+1-1)-5\\=4(x+1)^2-9\\=(2(x+1)-3)(2(x+1)+3)\\=(2x-1)(2x+5)\\x-intercepts\ are\ x=\frac{1}{2} \ and\ x=-\frac{5}{2} \\$

Part B:

x² coefficient is 4 >0 thus a minimun

as y=4(x+1)²-9 : vertex is (-1,-9)

Proof: see picture

Sorry for Part c: I don't know

In France, we make an array of (x,f(x)) and then plot the severals points.

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Answer:

Step-by-step explanation:

Alright, lets get started.

Lets find slope for both bikes one by one

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There are two points on the graph of Bike 1, these two points are (2,3) and (4,6)

So the slope for bike 1 is : $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

So the slope for bike 1 is : $\frac{6-3}{4-2}$

So the slope for bike 1 is : $\frac{3}{2}$

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