Answer:
59°
Step-by-step explanation:
From the diagram, shown in the attachment line x and y are parallel lines.
Angle 7 and angle 6 are angles on a straight line.
The two angles will add up to 180 degrees.
But angle 7 measures 121°.
This implies that:
Solve for angle 6 to get;
\
I think it’s can’t be determined because we need to know at least 2 angles of a train for.
This would be a combination I believe not a permutation so the equation to use would be nCr= n!/(n-r)!r!
So 10C2=45
8x-5y=11
4x-3y=5
solution;
4(8x-5y=11)
8(4x-3y=5)
it becomes, [32x-20y=44
- [32x-24y=40
(32x-32x)+(20y--24y)=44-40
it becomes 20y+22y=4
44y=4, dividing by 44 on both sides, it becomes y=1/11
thus, y=1/11 but 4x-3y=5
4x=5+3y
4x=5+3/11
4x=55/11+3/11
4x=58/11, cross multiplying, it becomes. 44x=58
x=58/44
x=29/22
therefore, x=29/22 and y=1/11
Answer:
0.6m^(10)
Step-by-step explanation:
1.2m^(4-n) *0.5m^(n+6)
Regroup
(1.2 * 0.5) * m^(4 - n) * m^(n + 6)
When multipling numbers with the same base, sum the exponents
0.6m^(10)