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Svetllana [295]
4 years ago
12

X-y=2 and x+y=-2 sove by graphing please and show the solution

Mathematics
1 answer:
eimsori [14]4 years ago
5 0

Answer:

The answer to your question is There is only one solution (0, -2)

Step-by-step explanation:

Data

Equation 1     x - y = 2

Equation 2    x + y = -2

Solve for y

Equation 1          y = x -2

                          y = x - 2

Equation 2         y = - x - 2

See the graph below

These lines cross in point (0 ,-2), that is the only solution.

If the lines have not crossed, they were parallel lines.

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weeeeeb [17]

Answer:

<h2>x = 0, y = 5, z = 3</h2>

Step-by-step explanation:

x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right

\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right

\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}

7 0
3 years ago
Convert into mixed fraction 48 by 8
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Answer:

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4 0
3 years ago
Angle A and angle B are complementary. m Angle A = 54 and M angle B = 2x+2. What is the m angle B
Gnom [1K]

Answer:

m=17

Step-by-step explanation:

Complementary means they add to equal 90 degrees.

1) 90-A=36

2)36=2x+2

3) Subtract 2 from both sides, 34=2x

4) Divide by 2 17=x

4 0
3 years ago
If m (x) = StartFraction x + 5 Over x minus 1 EndFraction and n(x) = x – 3, which function has the same domain as (m circle n) (
Andrew [12]

Answer:

The function h (x) = StartFraction 11 Over x minus 4 EndFraction

has the domain of h (x) = ( - ∞, 4) U (4, ∞ ) which is same as the

domain of (m ∘ n)(x) = ( - ∞, 4) U (4, ∞ ).

Step-by-step explanation:

m (x) = StartFraction x + 5 Over x minus 1 and n(x) = x – 3

As m (x) could be written as:

m(x) = \frac{x+5}{x-1}

n(x) = x – 3

(m ∘ n)(x) = m(n(x)) = m(x – 3)

              = \frac{(x-3) + 5}{(x-3) - 1}

              = \frac{x+2}{x-4}

In order to find the domain of (m ∘ n)(x) = \frac{x+2}{x-4}, we need to

make sure that denominator can not be zero,

So,

     x - 4 = 0

     x = 4    

So, our domain can be anything except for 4.

Hence, Domain = D = ( - ∞, 4) U (4, ∞ )

Now, compare the domain of (m ∘ n)(x) i.e D = ( - ∞, 4) U (4, ∞ ) with all the options:

Option A: h (x) = x + 5 / 11

Option A has the Domain of h (x) = Set of all real numbers

So, Option A is false.

Option B: h (x) = 11 / x - 1

                        x - 1 = 0

                         x = 1

Option B has the domain of h (x) = ( - ∞, 1) U (1, ∞ )

So, Option B is false.

Option C: h (x) = 11 / x - 4

                        x - 4 = 0

                         x = 4

Domain C has the domain of h (x) = ( - ∞, 4) U (4, ∞ )

So, Option C is true.

Option D: h (x) = 11 / x - 3

                        x - 3 = 0

                         x = 3

Option D has the domain of h (x) = ( - ∞, 3) U (3, ∞ )

So, option D is also false.

Hence, only option C is true as the option C i.e. h (x) = StartFraction 11 Over x minus 4 EndFraction has the domain of h (x) = ( - ∞, 4) U (4, ∞ ) which is same as the domain of (m ∘ n)(x) = ( - ∞, 4) U (4, ∞ ).

keywords: Domain, composite function

Learn more about the domain of function from brainly.com/question/13020740

#learnwithBrainly

4 0
4 years ago
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