Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.
![\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Neither one of the slopes are going to be minus. It means you are travelling backwards in time, which is wonderful if you are a sci-fi fan, but not so good if you are Sharon. A and D has Sharon going from 70 to 0. That can't be happening so both are wrong.
Now you have to decide between B and C. The intersection point has Sharon going upwards until she is 20. She started out at 70. The graph has John starting at 70. That's not right.
So we've eliminated A,D and now C.
The answer must be B. They meet when Sharon is 90 and John is about 22.5 which is what it should be.
Answer:
P(success at first attempt) = 0.1353
Step-by-step explanation:
This question follows poisson distribution. Thus, the formula is;
P(k) = (e^(-G) × (G)k)/k!
where;
G is number of frames generated in one frame transmission time(or frame slot time)
Let's find G.
To do this, we need to find number of frames generated in 1 slot time which is given as 50 ms.
Now, in 1000 ms, the number of frames generated = 50
Thus; number of frames generated in 50 ms is;
G = (50/1000) × 50
G = 2.5
To find the chance of success on the first attempt will be given by;
P(success at first attempt) = P(0) = e^(-G) = e^(-2) = 0.1353
3 x 7 because three, seven times is 21
85/5
(50+35)/5
50/5 + 35/5
10+7=17
