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3 years ago

I don't understand how to sole this problem !!!!

Mathematics

2 answers:

pickupchik [31]3 years ago

7 0

First we do shoulder bag:

boyakko [2]3 years ago

6 0

12 because 6x2 equals 12

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A triangular playground has sides that are lengths 2x feet, x-1 feet and x feet. If the perimeter of this playground is 27 feet,

Keith_Richards [23]

Answer:

The lengths of the sides of the playground are 14 feet, 6 feet, 7 feet

Step-by-step explanation:

At first, let us find the perimeter of the playground

∵ Perimeter of a triangle is P = S1 + S2 + S3

∵ The sides of the triangular playground are (2x) ft, (x - 1) ft, and x ft

∴ S1 = 2x, S2 = x - 1, S3 = x

→ Substitute them in the rule of the perimeter above

∵ P = 2x + x - 1 + x

→ Add the like terms

∴ P = (2x + x + x) - 1

∴ P = 4x - 1

∵ The perimeter of this playground is 27 feet

∴ P = 27

→ Equate the two values of P

∴ 4x - 1 = 27

→ Add 1 to both sides

∴ 4x - 1 + 1 = 27 + 1

∴ 4x = 28

→ Divide both sides by 4

∵ $\frac{4x}{4}$ = $\frac{28}{4}$

∴ x = 7

→ Substitute the value of x in each side to find their lengths

∵ S1 = 2(7)

∴ S1 = 14 feet

∵ S2 = 7 - 1

∴ S2 = 6 feet

∵ S3 = 7 feet

∴ The lengths of the sides of the playground are 14 feet, 6 feet, 7 feet

7 0

3 years ago

Whats 15+<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bq%7D%7B6%7D%20" id="TexFormula1" title=" \frac{q}{6} " alt=" \frac{q}{6}

coldgirl [10]

15+(q/6)=-21

Subtract 15 from both sides
q/6= -36

Multiply both sides by 6.
q= -216

8 0

4 years ago

What percentage is 52.54of 142 million

MariettaO [177]

The answer is 74,606,800
I you need an equation use 142 million times(multiplication) by 52.54 percent.
I hoped this helped :))

5 0

3 years ago

Read 2 more answers

There were 42 apples in each crate. 12 such crates of apples were delivered to a factory. 4 apples were rotten and had to be thr

algol [13]

Answer:

50 boxes

Step-by-step explanation:

first we can find how many apples there are

42*12=504

then subtract 4 of the rotten apples

504-4=500

then find how many boxes there can be

500/10=50

7 0

4 years ago

3. For the polynomial g(x) = x^4 - 8x^3 + 23^2 - 26x + 10, you are told that the zeros include x=1, x = -3 + i, and x = 3+i.

saveliy_v [14]

Step-by-step explanation:

If the polynomial has complex roots, the conjugates of those complex roots must also be part of the zeroes.

Therefore x = -3 - i and x = 3 - i are also zeroes of g(x). However this means that g(x) has 5 solutions when the degree of g(x) is 4. This is impossible, and hence the list is incorrect.

If either of the complex roots (x = -3 + i or x = 3 + i) had a multiplicity of 2, their conjugates will also have a multiplicity of 2, which is impossible as discussed previously.

Therefore x = 1 has a multiplicity of 2.

We have

x⁴ - 8x³ + 23x² - 26x + 10 = (x - 1)²(Ax² + Bx + C).

= (x² - 2x + 1)(Ax² + Bx + C)

= Ax⁴ + (B - 2A)x³ + (A + C - 2B)x² + (B - 2C)x + C

By Comparing Coefficients,

A = 1,

B - 2A = -8,

A + C - 2B = 23,

B - 2C = -26,

C = 10

Solving them we get A = 1, B = -6 and C = 10.

Hence x⁴ - 8x³ + 23x² - 26x + 10

= (x - 1)²(x² - 6x + 10).

Using the Quadratic Formula on x² - 6x + 10,

we find that the correct complex roots are

x = 3 + i and x = 3 - i.

Hence,

the zeroes of g(x) are x = 1, x = 3 + i and x = 3 - i.

8 0

3 years ago