Answer:
sqrt(98) aka ![\sqrt{98}](https://tex.z-dn.net/?f=%5Csqrt%7B98%7D)
Step-by-step explanation:
To find the third side we need to use the Pythagorean theorem (a^2 + b^2 = c^2) so let 3 = a and b = sqrt(89) so a^2 = 9 and for b^2 just ignore the square root so b^2 = 89 then we add 9 and 89 89 + 9 = 98 so c^2 = 98 then we do the square root of 98 since the square root of 98 isn't a whole number/ has a decimal we just leave it written as sqrt(98)
Negative minus negative greater negative get rid of the ()
Complete the recursive formula of the geometric sequence -0.56\,,-5.6\,,-56\,,-560,...−0.56,−5.6,−56,−560,...Minus, 0, point, 56
pentagon [3]
Answer:
The recursive formula is:
Cn = 10C(n-1)
Step-by-step explanation:
Given the geometric sequence.
-0.56, -5.6, -56, -560, ...
The common ratio is
-5.6/-0.56 = -56/-5.6 = -560/-56 = ... = 10
The recursive formula is easily
Cn = C(n-1) × 10
That is a number is ten times the preceding number.
8 action, 3 comedy, 5 drama....total = 16 dvd's
P(2 action, then a comedy)...without replacement
8/16 * 7/15 * 3/14 = (8 * 7 * 3) / (16 * 15 * 14) = 168/3360 = 1/20
Thts the answer because 8 is bigger than X the arrow goes to the left because 8 is bigger than numbers 1-7