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Cerrena [4.2K]
3 years ago
13

*Please Help* (20 POINTS)

Mathematics
1 answer:
Ivahew [28]3 years ago
8 0
Your fraction is: 2/3
This shows the slope, which is rise(vertical) over run(horizontal)
Hope this helps!
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Brain cells aren’t working right now sorry please help
balandron [24]

Answer:

Step-by-step explanation:

6 lol

7 0
3 years ago
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What is the remainder of (4x2 + 7x-1)= (4 + x)?<br>A. -9x – 1<br>B.23x – 1<br>C.35<br>D.-37​
bearhunter [10]

Answer: I don't know what you meant by remainder but i hope this helps :)

x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\

Step-by-step explanation:

\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}

\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\

\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}

6 0
3 years ago
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Evaluate 5xi^11 + 2xi^5
katovenus [111]
That’s how you solve complex numbers.

6 0
3 years ago
If a canoe travels with a speed of A mph for 3 hours, and then with a speed of B mph for the rest of the journey, how long does
Mandarinka [93]

Answer:

t = (C - 3*A)/B + 3

Step-by-step explanation:

Given in the question that,

the speed with which canoe travelled for first 3 hours = A

the speed with which he travelled for any and all time thereafter = B

As we do not know the values of A, B, or C, so the answer will be an expression for C in terms of A and B.

<h3>Formula to use</h3>

distance = speed x time

C = A*3 + B*(t-3)

Rearranging and solving for t

C - (A*3) = B*(t-3)

C - (A*3) = Bt - B3

C - (A*3) + B3 = Bt

t = C - (A*3) + B3 / B

or

t = (C - 3*A)/B + 3

4 0
3 years ago
6 - y = 12 is what lol
notsponge [240]

Answer:

=−6

Step-by-step explanation:

7 0
3 years ago
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