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podryga [215]
3 years ago
13

Write 3 times the square root of 2 plus 2 times the square root of 3 in simplest form.

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0

Answer:

D

Step-by-step explanation:

3\sqrt{2} + 2\sqrt{3}

is in simplest form and cannot be simplified further


You might be interested in
Which unit would you use to measure the weight of a car
statuscvo [17]

Answer:

Tonnes

Step-by-step explanation:

8 0
3 years ago
Aaron wants to make a path to guide guest through the conservation area.He uses rolls of rope to make the path.He uses 3/4 of a
mel-nik [20]

Answer:

Aaron needs <u>2 more rolls</u> to complete the path.

Step-by-step explanation:

Given:

Total rolls Aaron has = 4

Part of path covered by using \frac{3}{4} of a roll = \frac{1}{8}

So, in order to find the number of rolls required to cover the complete path is given using the unitary method.

Rolls used for \frac{1}{8} of a path = \frac{3}{4}

Therefore, rolls used to cover the whole path is given by dividing the rolls used for one-eighth of the path and the path covered. This gives,

=\frac{3}{4}\div \frac{1}{8}

=\frac{3}{4}\times \frac{8}{1}

=\frac{3\times 8}{4\times 1}

=\frac{24}{4}

=6\ rolls

Now, rolls required to complete the path is 6. But Aaron has only 4 rolls.

So, he will need 6 - 4 = 2 rolls more to complete the path.

5 0
4 years ago
In a local ice sculpture contest, one group sculpted a block into a rectangular based pyramid. The dimensions of the base were 3
m_a_m_a [10]

Answer:

1. The amount of ice needed = 18 m²

2. The amount of fabric needed to manufacture the umbrella is 0.76 m²

3. The height of the cone, is 3.75 cm

4. The dimensions of the deck are;

Width = 28/3 m, breadth = 28/3 m

The area be 87.11 m²

5.   The dimensions of the optimal design for setting the storage area at the corner, we have;

Width = 10m

Breadth = 10 m

The dimensions of the optimal design for setting the storage area at the back of their building are;

Width = 7·√2 m

Breadth = 7·√2 m

Step-by-step explanation:

1. The amount of ice needed is given by the volume, V, of the pyramid given by V = 1/3 × Base area × Height

The base area = Base width × Base breadth = 3 × 5 = 15 m²

The pyramid height = 3.6 m

The volume of the pyramid = 1/3*15*3.6 = 18 m²

The amount of ice needed = 18 m²

2. The surface area of the umbrella = The surface area of a cone (without the base)

The surface area of a cone (without the base) = π×r×l

Where:

r = The radius of the cone = 0.4 m

l = The slant height = √(h² + r²)

h = The height of the cone = 0.45 m

l = √(0.45² + 0.4²) = 0.6021 m

The surface area = π×0.4×0.6021 = 0.76 m²

The surface area of a cone (without the base) = 0.76 m²

The surface area of the umbrella = 0.76 m²

The amount of fabric needed to manufacture the umbrella = The surface area of the umbrella = 0.76 m²

3. The volume, V, of the cone = 1/3×Base area, A, ×Height, h

The volume of the cone V = 150 cm³

The base area of the cone A = 120 cm²

Therefore we have;

V = 1/3×A×h

The height of the cone, h = 3×V/A = 3*150/120 = 3.75 cm

4. Given that the deck will have railings on three sides, we have;

Maximum dimension = The dimension of a square as it is the product of two  equal maximum obtainable numbers

Therefore, since the deck will have only three sides, we have that the length of each side are equal and the fourth side can accommodate any dimension of the other sides giving the maximum dimension of each side as 28/3

The dimensions of the deck are width = 28/3 m, breadth = 28/3 m

The area will then be 28/3×28/3 = 784/9 = 87\frac{1}{9} =87.11 m²

5. The optimal design for setting the storage area at the corner of their property with four sides is having the dimensions to be that of of a square with equal sides of 10 m each as follows;

Width = 10m

Breadth = 10 m

The optimal design to have the storage area at the back of their building having a fence on only three sides, is given as follows;

Storage area specified = 98 m²

For optimal use of fencing, we have optimal side size of fencing = s = Side length of a square

s² = 98 m²

Therefore, s = √98 = 7·√2 m

Which gives the width = 7·√2 m and the breadth = 7·√2 m.

8 0
3 years ago
A number cube (dice) is rolled and a letter is selected from the word GIRAFFE. What is the compound probability of P ( 4 and F)
Furkat [3]

Answer:

P (4 and F) = 1 in 21 or 4.76%

P(EVEN NUMBER AND VOWEL) = 3 in 14 or 21.43%

Step-by-step explanation:

The probability of rolling a four on a die is 1 in 6.

The probability of picking the letter F in the word GIRAFFE is 2 in 7.

Therefore:

P (4\ and\ F)=P(4)*P(F)\\ P (4\ and\ F)=\frac{1}{6}*\frac{2}{7}\\    P (4\ and\ F)=\frac{1}{21}= 4.76\%

The probability of rolling an even number (2, 4 or 6) on a die is 3 in 6.

The probability of picking a vowel (A, E, I) in the word GIRAFFE is 3 in 7.

Therefore:

P (Even\ and\ Vowel)=P(Even)*P(Vowel)\\ P (Even\ and\ Vowel)=\frac{3}{6}*\frac{3}{7}\\     P (Even\ and\ Vowel)=\frac{3}{14}= 21.43\%

5 0
3 years ago
Solve the following subtraction problems. a. 8 mi. 133 yd. 2 ft. – 5 mi. 107 yd. 2 ft. b. 2 yd. 2 ft. 6 in. – 1 ft. 11 in. c. 6
aksik [14]

Let's keep in mind the conversion factors between mile, yard, feet and inches:

1 mile = 1760 yards

1 yard = 3 feets

1 feet = 12 inches


a) 3 mi. 26 yd.

We have:

8 mi. 133 yd. 2 ft. –

5 mi. 107 yd. 2 ft =

Here, we can simply do the substraction of each term, and we get:

(8-5) mi  (133-107) yd  (2-2) ft =

3 mi. 26 yd  0 ft =

3 mi. 26 yd.


b) 2 yd. 7 in.

We have:

2 yd. 2 ft. 6 in. –

0 yd.  1 ft. 11 in.

Here, we need to convert 1 feet into 12 inches and add them to the inches in the first term as follows:

2 yd. 2 ft. 6 in. = 2 yd. 1 ft. (6+12) in. = 2 yd. 1 ft. 18 in.

So now the subtraction becomes:

2 yd. 1 ft. 18 in. –

0 yd.  1 ft. 11 in.

and now we can simply do the substraction of each term, and we get:

(2-0) yd.  (1-1) ft.  (18-11) in. =

2 yd. 0 ft. 7 in. =

2 yd. 7 in.


c)  5 yd. 5 in.

We have:

6 yd.  0 ft. 0 in. –

0 yd.  2 ft. 7 in.

We have to "move" 1 yard into  feets and inches in the first term, as follows:

6 yd.  0 ft. 0 in. = 5 yd. 3 ft. 0 in. = 5 yd. 2 ft. 12 in.

And now the subtraction becomes:

5 yd. 2 ft. 12 in. -

0 yd.  2 ft. 7 in. =

5 yd.  0 ft. 5 in. =

5 yd. 5 in.


d) 8 in.

We have:

8 yd. 0 ft. 4 in. –

7 yd. 2 ft. 8 in.

Again, let's convert the first term, moving yards into feets and inches:

8 yd. 0 ft. 4 in. = 7 yd. 3 ft. 4 in. = 7 yd. 2 ft. (4+12) in. = 7 yd. 2 ft. 16 in.

So now the subtraction is:

7 yd. 2 ft. 16 in. -

7 yd. 2 ft. 8 in. =

0 yd. 0 ft. 8 in. =

8 in.

3 0
4 years ago
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