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salantis [7]
3 years ago
14

HELP!!! 10 POINTS OFFERED!!THIS IS MY LAST QUESTION!!

Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0

Answer:

A (-2,8)          B (-1,5)                  C (-6,2)

A(-2,-7)         B(-5,-8)                  C(-8,-3)

Step-by-step explanation:

                                  x,y                     x,y                          x,y

                              A(7,-2) ,              B(8,-5) ,                  C(3,-8)

translation               (7-9),(-2+10)     (8-9),(-5+10)          ( 3-9),(-8+10)

(x-9) and (y+10)        (-2,8)                    (-1,5)                     (-6,2)

when rotation 270 degrees counterclockwise around the origin:

A(x,y ) Then A'(-y,x) means switch x and y and make x negative

A(7,-2 )  rotation 270 degrees counterclockwise (-2,-7)

B(8,-5)        to (-5,-8)

C(3,-8)        to (-8,-3)

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] It is claimed that 42% of US college graduates had a mentor in college. For a sample of college graduates in Colorado, it was
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Answer:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

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Step-by-step explanation:

Information given

n=1045 represent the random sample selected

X=502 represent the college graduates with a mentor

\hat p=\frac{502}{1045}=0.480 estimated proportion of college graduates with a mentor

p_o=0.42 is the value that we want to test

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is higher than 0.42, the system of hypothesis are.:  

Null hypothesis:p \leq 0.42  

Alternative hypothesis:p > 0.42  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

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3 years ago
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