Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:
![\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac2n%5Cright%5D%2C%5Cleft%5B%5Cdfrac2n%2C%5Cdfrac4n%5Cright%5D%2C%5Cleft%5B%5Cdfrac4n%2C%5Cdfrac6n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7B2%28n-1%29%7Dn%2C2%5Cright%5D)
Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,
where 
. Each interval has length 
.
At these sampling points, the function takes on values of
We approximate the integral with the Riemann sum:
Recall that
so that the sum reduces to
Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:
Just to check:
Answer: 314 mm
Step-by-step explanation:
Area of a circle is π*r^2
r is radius and π is 3.14
here the radius is 10
3.14 * 10^2 = 3.14 * 100 = 314
Answer:
(3w - 7)(3w + 7)
Step-by-step explanation:
The expression is a difference of squares and factors in general as
a² - b² = (a - b)(a + b)
Thus
9w² - 49
= (3w)² - 7²
= (3w - 7)(3w + 7)
Answer: z=67-at
————
a-45
Volume of a cylinder= (height) x area of the base (circle)
We know the height = 160 cm (given), let's find the radius of the base.
The circumference of the base = 87.92 = 2πR==> R=87.92/(2π) =13.993 cm
Area of circle = πR²=π(13.993)² = 615.128 cm²
Hence the volume of the cylinder = 615.128 x 160 = 92,420.48 cm³
