Answer:
Step-by-step explanation:
a) H0: 
Ha: 
(Two tailed test at 5% significance level)
b) n=30
Mean difference = 
Std error of mean = 
b) Test statistic t = mean diff/std error = -1.552
df = 30-1 =29
p value=0.0657
c) Since p > 0.05 our signi. level, we accept null hypothesis.
There is no significant difference between the means.
d) Using critical value we find that test statistic is > critical value left
So accept H0
Answer:
ok on my way to do so!!!!!!
Answer:
-5
Step-by-step explanation:
x² - 4x - 45 = 0
(x - 9)(x + 5) = 0
x = 9 or -5
x² - 25 = 0
(x + 5)(x - 5) = 0
x = 5 or -5
-5 is a common factor between both of them