Check the picture below.
so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.
![\stackrel{\textit{area of the semicircle}}{\cfrac{1}{2}\pi r^2}\implies \cfrac{1}{2}(\stackrel{\pi }{3.14})(2)^2\implies 3.14\cdot 2\implies 6.28 \\\\\\ \stackrel{\textit{area of the square}}{(4)(4)}\implies 16 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{sum of both areas}}{16+6.28=22.28}~\hfill](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20semicircle%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%5Cpi%20r%5E2%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cstackrel%7B%5Cpi%20%7D%7B3.14%7D%29%282%29%5E2%5Cimplies%203.14%5Ccdot%202%5Cimplies%206.28%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20square%7D%7D%7B%284%29%284%29%7D%5Cimplies%2016%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsum%20of%20both%20areas%7D%7D%7B16%2B6.28%3D22.28%7D~%5Chfill)
Answer:
Step-by-step explanation:
In this scenario, You've asked about the Chutney (Sauce/Raita).
<em>Ok, So let's suppose you are making a "Chutney"</em>
- The first you need is the right amount of ingredients.
- Their quantity and they must be fresh "<em>To make every effort of yours worth it!</em>"
- Add it into a bowl or a dish that you have at the time (Or a big one to be on the safe side)
- At the end mix the ingredients well, So that they don't spoil taste of the one who is taking it.
The amount of milliliters (Weight measurement) depends upon the amount of usage/intake that one is taking.
It could be a few hundred (gms. or some Kg's).
That totally depends up on your choice
B is rational. B is the correct answer. B is rational.
Answer:
In this particular case, Circle M has circumference 11π, or approximately 34.6 units.
Step-by-step explanation:
The circumference of a circle of diameter d is C = πd.
In this particular case, Circle M has circumference 11π, or approximately 34.6 units.
