Answer:
The one opposite of 100°, as the bigger the angle, the bigger the opposing side, is the biggest.
By the same logic, the one opposite 45° is the next biggest.
Continuing with that, the one opposite the black one (which would equal 35°, I think) is the smallest.
Answer:

Step-by-step explanation:









Hope this helps!
Given:
The figure of triangle ABC.
The area of the triangle ABC is D.

To find:
The value of m and n in the given expression.
Solution:
Let h be the height of the triangle ABC.
Area of a triangle is:

Where, b is the base and h is the height of the triangle.

The area of the triangle ABC is D.


...(i)
In a right angle triangle,


[Using (i)]
...(ii)
We have,
...(iii)
On comparing (ii) and (iii), we get


Therefore, the required values are
.