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gulaghasi [49]
2 years ago
7

Picture is below (brainliest)

Mathematics
1 answer:
RSB [31]2 years ago
4 0
The answer would be B. supplementary means the angles add up to 180. so if you subtract 72 from 180, you get 108
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Determine if the following equation has "One Solution", "No Solutions", or "Infinite Many Solutions".
Novosadov [1.4K]
First, distribute the 2.
2x+6=6+2x
These are the same, so therefore it is infinitely many, because whatever you plug in for x will work.
7 0
3 years ago
Read 2 more answers
One bar of candy A and two bars of candy B have 777 calories. Two bars of candy A and one bar of candy B contain 783 calories. F
RSB [31]

Answer:

A has 263 calories

B has 257 calories

Step-by-step explanation:

system of equations:

a + 2b = 777

2a + b = 783

I multiplied the first equation by -2 to eliminate the 'a' terms

  -2a - 4b = -1554

+ <u> 2a  + b =    783</u>

         -3b = -771

b = 257

solve for 'a'

a + 2(257) = 777

a + 514 = 777

a = 263

4 0
3 years ago
Andrea bought 10 bagels and 6 muffins at the bakery. of these items 2/3 of the bagels were multigrain and 3/5 of the muffins wer
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The answer that makes the most scents is. 3 out of the five muffins
4 0
3 years ago
Select the diagram showing a pair of alternate interior angles:
Nat2105 [25]

The orange one is an example of alternate interior angles.

4 0
2 years ago
Classify each conic section and write its equations in standard form. Show work.
svp [43]

Answer:

The conic is ellipse of equation (x - 1)²/22 + (y + 4)²/44 = 1

Step-by-step explanation:

* Lets revise how to identify the type of the conic  

- Rewrite the equation in the general form,  

 Ax² + Bxy + Cy² + Dx + Ey + F = 0  

- Identify the values of A and C from the general form.  

- If A and C are nonzero, have the same sign, and are not equal  

 to each other, then the graph is an ellipse.  

- If A and C are equal and nonzero and have the same sign, then  

 the graph is a circle  

- If A and C are nonzero and have opposite signs, and are not equal  

then the graph is a hyperbola.  

- If either A or C is zero, then the graph is a parabola  

* Now lets solve the problem

The equation is 4x² + 2y² - 8x + 16y - 52 = 0

∴ A = 4 and C = 2 ⇒ same sign and different values

∴ The equation is ellipse

* The standard form of the ellipse is

  (x - h)²/a² + (y - k)²/b² = 1

- Lets try to make this form from the general form

- Group terms that contain the same variable, and move the

  constant to the opposite side of the equation

∴ (4x² - 8x) + (2y² + 16y) = 52

- Factorize the coefficients of the squared terms

∴ 4(x² - 2x) + 2(y² + 8y) = 52

- Complete the square for x and y

# To make completing square

- Divide the coefficient  of x (or y) by 2 and then square the answer

- Add and subtract this square number and form the bracket of

 the completing the square

# 2 ÷ 2 = 1 ⇒ (1)² = 1 ⇒ add and subtract 1

∴ 4[(x² - 2x + 1) - 1] = 4(x² - 2x + 1) - 4

- Rewrite as perfect squares ⇒ 4(x -1)² - 4

# 8 ÷ 2 = 4 ⇒ (4)² = 16 ⇒ add and subtract 16

∴ 2[(y² + 8y + 16) - 16] = 2(y² + 8y + 16)² - 32

- Rewrite as perfect squares ⇒ 2(y + 4)² - 32

∴ 4(x - 1)² - 4 + 2(y + 4)² - 32 = 52

∴ 4(x - 1)² - 4 + 2(y + 4)² = 32 + 4 + 52

∴ 4(x - 1)² + 2(y + 4)² = 88 ⇒ divide all terms by 88

∴ (x - 1)²/22 + (y + 4)²/44 = 1

8 0
2 years ago
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