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3 years ago

Karin wants to use the distributive property to mentally find the value of 19⋅42+19⋅58. Which expression can she use?

Mathematics

2 answers:

AnnyKZ [126]3 years ago

6 0

Answer:

Step-by-step explanation:

dont know how explain.

devlian [24]3 years ago

3 0

Answer:

$19( 42+ 58)$

Step-by-step explanation:

$19 \cdot 42+19 \cdot 58\\$

The common factor is 19

$19( 42+ 58)$

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Find an equation of the line described below. Write the equation is slope-intercept from ( solved for y), when possible. Through

Sladkaya [172]

Answer:

The equation of the line that is passing through the point (5,4) and is parallel to x-axis would be $y=4$

Step-by-step explanation:

Given that the line passes through the point (5,4).

As the line is parallel to the x-axis, the slope of the line would be zero.

And we have point (5,4) from which the line is passing.

So, $x_1=5\ ,\ y_1=4\ and\ m=0$

The equation of the line passing through point $(x_1,y_1)$ is

$y-y_1=m(x-x_1)\\y-4=0(x-5)\\y-4=0\\y=4$

So, the equation of the line that is passing through the point (5,4) and is parallel to x-axis would be $y=4$

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3 years ago

Maria's family drove 140 mi to her grandparents' house and averaged 56 mi/h on the way there. On the return trip, they avera

GaryK [48]

Answer: 5.3 Hours

Step-by-step explanation: 140 mi there at 56 mi per hour would be 2.5 hours. Then back 140 mi at 50 mi/h would be 2.8. 2.5 plus a 2.8 is 5.3 hours

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2 years ago

The heat index I is a measure of how hot it feels when the relative humidity is H (as a percentage) and the actual air temperatu

PSYCHO15rus [73]

Answer:

a) $I(95,50) = 73.19$ degrees

b) $I_{T}(95,50) = -7.73$

Step-by-step explanation:

An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

$I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}$

a) Calculate I at (T ,H) = (95, 50).

$I(95,50) = 45.33 + 0.6845*(95) + 5.758*(50) - 0.00365*(95)^{2} - 0.1565*95*50 + 0.001*50*95^{2} = 73.19$ degrees

(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.

This is the partial derivative of I in function of T, that is $I_{T}(T,H)$ . So

$I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}$

$I_{T}(T,H) = 0.6845 - 2*0.00365T - 0.1565H + 2*0.001H$

$I_{T}(95,50) = 0.6845 - 2*0.00365*(95) - 0.1565*(50) + 2*0.001(50) = -7.73$

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3 years ago

A hundred percent turned into a decimal

faltersainse [42]

100%=1.0 hope this helps

4 0

3 years ago

Read 2 more answers

URGENT <br>Perform the indicated operation and simplify the result.

yan [13]

Answer:

The answer to your question is: (2a - 1) / 4

Step-by-step explanation:

$\frac{12a^{2} - 3}{2} (2a + 1)^{-2} ( \frac{6}{(2a +1)^{-1} } \\$

$\frac{3(4a^{2} -1)}{2} \frac{1}{(2z + 1)^{2} } (\frac{2a + 1)}{6}$

$\frac{3(2a + 1)(2a- 1) (2a + 1)}{12(2a + 1)(2a + 1)}$

$\frac{(2a - 1)}{4}$

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3 years ago