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Rudik [331]
3 years ago
15

How can one determine the zeros of a function? 

Mathematics
2 answers:
OLEGan [10]3 years ago
8 0
<span>They are the values of 'x' that make the function zero.

If you graph the function, they are the values of 'x' where the graph
crosses the x-axis.</span>
puteri [66]3 years ago
6 0
the\ argument\ x\, for\ which\ the\ value\ y\ of\ the\ function\ is\ zero\\\\e.g.\\y=2x-6\ \ \ \Rightarrow\ \ \  the\ zeros\ of\ a\ function\ is\ x=3\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (y=2\cdot3-6=6-6=0)\\\\y=x^2+8x\ \ \ \Rightarrow\ \ \  the\ zeros\ of\ a\ function\ are\ x=0\ \ \ or\ \ \ x=-8\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (y_1=0^2+8\cdot0=0;\  y_2=(-8)^2+8\cdot(-8)=64-64)
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Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Because MK is a diameter, then angle L is a right angle. We already know that the measure of angle K is 50, so the measure of angle M has to be 40 because of the triangle angle-sum theorem. The rule for inscribed angles and the arcs they cut off is that the angle is half the measure of its intercepted arc or, likewise, the arc is twice the measure of the angle that cuts it off. Since arc LK is across from angle M and is cut off by angle M, then arc LK is twice the measure of angle M, and is 80. That's the same reason why angle L is 90; arc MK is a semi-circle, with a degree measure of 180, and angle L is half of that.

Arc LK = 80

5 0
3 years ago
Jane and Lee had dinner at The Palace The bill totaled $20 30 with tax The service
kirza4 [7]

Answer:

$3.45

Step-by-step explanation:

$20.30 / 10  = $2.30 = 10%

$2.30 / 2  = $1.15 = 5%

$2.30 + $1.15 = $3.45 = 15%

3 0
3 years ago
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NikAS [45]

Divide 4 by 1/10.

So, 4 ÷ 1/10 becomes 4 x 10/1.

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Did you follow?

6 0
3 years ago
Read 2 more answers
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