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Rudik [331]
3 years ago
15

How can one determine the zeros of a function? 

Mathematics
2 answers:
OLEGan [10]3 years ago
8 0
<span>They are the values of 'x' that make the function zero.

If you graph the function, they are the values of 'x' where the graph
crosses the x-axis.</span>
puteri [66]3 years ago
6 0
the\ argument\ x\, for\ which\ the\ value\ y\ of\ the\ function\ is\ zero\\\\e.g.\\y=2x-6\ \ \ \Rightarrow\ \ \  the\ zeros\ of\ a\ function\ is\ x=3\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (y=2\cdot3-6=6-6=0)\\\\y=x^2+8x\ \ \ \Rightarrow\ \ \  the\ zeros\ of\ a\ function\ are\ x=0\ \ \ or\ \ \ x=-8\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (y_1=0^2+8\cdot0=0;\  y_2=(-8)^2+8\cdot(-8)=64-64)
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You have been asked to build a scale model of your school out of toothpicks. imagine your school is 30 feet tall. your scale is
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\frac{37.8}{6.3} =6

ANSWER: The model would be 6 toothpicks tall.

To find out how many cotton swabs you'll need, we just divide 37.8 by how tall each swab is:

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3 years ago
Which formula gives the area of a rectangle?
Tpy6a [65]

Answer:

L*W=Area

Step-by-step explanation:

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3 years ago
Somebody please help me with this geometry work
dimulka [17.4K]

Answer:

m∠EGF = 65°  and m∠CGF = 115°

Step-by-step explanation:

Given;

∠EFG = 50°

EF = FG

Solution,

In ΔEFG m∠EFG = 50° and EF = FG.

Since triangle is an isosceles triangle hence their base angles are always equal.

∴m\angle FEG = m\angle EGF

Let the measure of ∠EGF  be x.

∴ m\angle FEG = m\angle EGF = x

Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."

m∠EFG + m∠FEG + ∠EGF = 180

50\°+x+x=180\°\\50\°+2x=180\°\\2x= 180\°-50\°\\2x=130\°\\x=\frac{130}{2}= 65\°

Hence

m∠EGF = 65°  

Also 'The sum of angles that are formed on a straight line is equal to 180°."

m∠EGF + m∠CGF = 180°

65° + m∠CGF = 180°

m∠CGF = 180° - 65° = 115°

Hence m∠EGF = 65°  m∠CGF = 115°

8 0
3 years ago
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