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S_A_V [24]
2 years ago
9

Please help me solve this

Mathematics
1 answer:
RSB [31]2 years ago
8 0

Step-by-step explanation:

a) f(1) = -1 → x = -1

b) g(1) = Undefined

c) f(x) = 1 → x= Undefined

d) g(x) = 1 → x= 5

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The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 13.1 years; the standard devia
Ilia_Sergeevich [38]

Answer:

<em>The probability between 16.1 and 17.6 years = 0.0214 years </em>

<em>The  Estimate  probability between 16.1 and 17.6 years = 2.14 years</em>

<em>Step-by-step explanation:</em>

<u><em>Step(i)</em></u>:-

Given the average of Population 13.1 years

The standard deviation of the Population = 1.5 years

<em>Let 'x' be the random variable in Normal distribution</em>

<em>Given x = 16.1</em>

         Z _{1} = \frac{x- mean}{S.D}

            =\frac{16.1-13.1}{1.5}

           = 2

       <em> Z₁ = 2</em>

<u><em>Step(ii):</em></u><em>-</em>

<em>Given x = 17.6</em>

      Z_{2}  = \frac{17.6- 13.1}{1.5}

<em>      Z ₂= 3</em>

<em> Z₁ = 2 and </em> <em>    Z ₂= 3 are both positive</em>

<em>The Estimate probability between 16.1 and 17.6 years</em>

<em>P( 16.1<x<17.6) = P( 2 < Z < 3)</em>

<em>                       </em> = A(3) - A(2)

                      =  0.49865 - 0.4772 (from normal table)

                     = 0.0214

<em>The probability between 16.1 and 17.6 years = 0.0214 years </em>

<em>                                                                        =  0.0214 ×100 </em>

<em>                                                                       = 2.14 years</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The  Estimate  probability between 16.1 and 17.6 years = 2.14 years</em>

                                                                                           

8 0
3 years ago
Read 2 more answers
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