How do you solve (Y-2)(y+4)

In 50 gram portion of cereal 8 grams of it are sugar which of the following represents the present of the 50 grams that is sugar

kipiarov [429]

Answer:

C

Step-by-step explanation:

8/50= 0.16

5 0

3 years ago

Read 2 more answers

The price of a buffet lunch is $14.80 per adult and $12 per children. William paid a total of $95.2 for a group of m adults and

lianna [129]

Answer:

$14.80(m) + $12(n) = $95.2

Solved:

$14.80(4) + $12(3) = $95.2

Step-by-step explanation:

m represents Adults ($14.80m) | n represents Children ($12n)

4 Adults times $14.80 equals $59.2

3 Children times $12 equals $36

Add $36 and $59.2 and you get $95.2

5 0

3 years ago

Read 2 more answers

Given that Cheryl is collecting data on car color, what type of data is she working with?

Airida [17]

A. Qualitative
Bc it includes colors

5 0

3 years ago

A group of veterinarians at a major veterinary hospital was interested in investigating a possible link between enteroliths, sto

klemol [59]

C. all horses that are diagnosed with enteroliths

3 0

3 years ago

According to the norms established for a reading comprehension test, eighth-graders should average 83.2 with a standard deviatio

joja [24]

Answer:

$t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73$

$p_v =P(t_{44}>2.73)=0.0045$

If we compare the p value and a significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=86.7$ represent the average life for the sample

$s=8.6$ represent the population standard deviation

$n=45$ sample size

$\mu_o =83.2$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a two tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu \leq 83.2$

Alternative hypothesis : $\mu > 83.2$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73$

Give the appropriate conclusion for the test

First we need to calculate the degrees of freedom given by:

$df=n-1=45-1=44$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{44}>2.73)=0.0045$

Conclusion

If we compare the p value and a significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

8 0

3 years ago