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3 years ago

If the mean of the data set 11, 19, 4a, 7a, 14a is 71, then what is the value of a?

Mathematics

1 answer:

Korvikt [17]3 years ago

7 0

Answer:

11+19+4a+7a+14a=71.30+25a=71.25a=71-30.a=1.64

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John received $9,000 in student loans. Part of the money he was able to borrow 7% simple interest, but on the rest of the money

Crank

0.07x+0.0825(9000-x)=706.25
Solve for x
X=2900 at 7%

9000-2900=6100 at 8.25%

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4 years ago

The diameter of a cart wheel is 26 inches. how far will it go in one rotation?

klasskru [66]

Answer:

the correct answer is 81.71 inch

Step-by-step explanation:

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3 years ago

Read 2 more answers

Which is the following descibes a median of a triangle

Firdavs [7]

According to the internet it states, The median of a triangle is a line segment joining the vertex of the triangle to the mid-point of its opposite side.

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2 years ago

Find dx/dt when y=2 and dy/dt=1, given that x^4=8y^5-240<br><br> dx/dt=

katrin2010 [14]

Answer:

The value of $\frac{dx}{dt}$ is $\frac{160}{x^3}$ .

Step-by-step explanation:

The given equation is

$x^4=8y^5-240$

We need to find the value of $\frac{dx}{dt}$ .

Differentiate with respect to t.

$4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0$ $[\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]$

$4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}$

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

$4x^3\frac{dx}{dt}=40(2)^4(1)$

$4x^3\frac{dx}{dt}=40(16)(1)$

$4x^3\frac{dx}{dt}=640$

Divide both sides by 4x³.

$\frac{dx}{dt}=\frac{640}{4x^3}$

$\frac{dx}{dt}=\frac{160}{x^3}$

Therefore the value of $\frac{dx}{dt}$ is $\frac{160}{x^3}$ .

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3 years ago

One centimeter is what times as long as one millimeter

Likurg_2 [28]

One centimeter equals 10 millimeters.

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3 years ago

If the mean of the data set 11, 19, 4a, 7a, 14a is 71, then what is the value of a?​

If the mean of the data set 11, 19, 4a, 7a, 14a is 71, then what is the value of a?