Answer:
3x^2-6x+3=0
x^2-2x+1=0
x^2-x-x+1=0
x(x-1)-(x-1)=0
(x-1)(x-1)=0
x=1,1
so x has only one answer
so it intersects only one time
So you need to come up with a perfect square that works for the x coefficients.
like.. (2x + 2)^2
(2x+2)(2x+2) = 4x^2 + 8x + 4
Compare this to the equation given. Our perfect square has +4 instead of +23. The difference is: 23 - 4 = 19
I'm going to assume the given equation equals zero..
So, If we add subtract 19 from both sides of the equation we get the perfect square.
4x^2 + 8x + 23 - 19 = 0 - 19
4x^2 + 8x + 4 = - 19
complete the square and move 19 over..
(2x+2)^2 + 19 = 0
factor the 2 out becomes 2^2 = 4
ANSWER: 4(x+1)^2 + 19 = 0
for a short cut, the standard equation
ax^2 + bx + c = 0 becomes a(x - h)^2 + k = 0
Where "a, b, c" are the same and ..
h = -b/(2a)
k = c - b^2/(4a)
Vertex = (h, k)
this will be a minimum point when "a" is positive upward facing parabola and a maximum point when "a" is negative downward facing parabola.
Answer:
x=4,-4
Step-by-step explanation:
I believe its C, but its up to you to listen to me
The statements that are true about the dollhouses is: 1,4,5.
<h3>True statement about dollhouse</h3>
The space inside dollhouse 1 can be found using the equation V = 6 (6) (5) + one-half (6) (6) (4).
Space inside dollhouse 1:
V = 6 (6) (5) + 1/2 (6) (6) (4)
V=180+72
V=252 inches
The space inside dollhouse 2 can be found using the equation
V = 6 (6) (5) + 1/3 (6) (6) (4)
V=180+48
V=228
The space inside dollhouse 1 is 24 inches cubed greater than the space inside dollhouse 2.
V1=252
V2=228
Hence:
252-228=24 inches cubed
V1 ≥V2
Therefore the statements that are true about the dollhouses is: 1,4,5.
Learn more about True statement about dollhouse here:brainly.com/question/22406331
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