Total ways = {AAA, AAB, ABA, BAA, ABB, BAB, BBA, BBB}
Ways at least one counter with side A = {AAA, AAB, ABA, BAA, ABB, BAB, BBA}
Hence, the number of ways at least one counter with side A = 7.
Answer:
Step-by-step explanation:
Answer: =2/15
Step-by-step explanation: Hope this help :D