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Deffense [45]
3 years ago
7

the three counters shown in the table are used for a board game. If the counters are tossed , how many ways can at least one cou

nter with side A occur?
Mathematics
1 answer:
Elena L [17]3 years ago
8 0

Total ways = {AAA, AAB, ABA, BAA, ABB, BAB, BBA, BBB}

Ways at least one counter with side A = {AAA, AAB, ABA, BAA, ABB, BAB, BBA}

Hence, the number of ways at least one counter with side A = 7.

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iren2701 [21]

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RBCs are disc-shaped with a flatter, concave center. This biconcave shape allows the cells to flow smoothly through the narrowest blood vessels. ... Many RBCs are wider than capillaries, but their shape provides the needed flexibility to squeeze through

8 0
2 years ago
Solve for x. 21/2x−3/4(2x+5)=3/8
Savatey [412]
Simplify \frac{21}{2}x
​2
​
​21
​​ x to \frac{21x}{2}
​2
​
​21x
​​
\frac{21x}{2}-\frac{3}{4}(2x+5)=\frac{3}{8}
​2
​
​21x
​​ −
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​
​3
​​ (2x+5)=
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​
​3
​​

2 Simplify \frac{3}{4}(2x+5)
​4
​
​3
​​ (2x+5) to \frac{3(2x+5)}{4}
​4
​
​3(2x+5)
​​
\frac{21x}{2}-\frac{3(2x+5)}{4}=\frac{3}{8}
​2
​
​21x
​​ −
​4
​
​3(2x+5)
​​ =
​8
​
​3
​​

3 Multiply both sides by 44 (the LCM of 2, 42,4)
42x-3(2x+5)=\frac{3}{2}42x−3(2x+5)=
​2
​
​3
​​

4 Expand
42x-6x-15=\frac{3}{2}42x−6x−15=
​2
​
​3
​​

5 Simplify 42x-6x-1542x−6x−15 to 36x-1536x−15
36x-15=\frac{3}{2}36x−15=
​2
​
​3
​​

6 Add 1515 to both sides
36x=\frac{3}{2}+1536x=
​2
​
​3
​​ +15

7 Simplify \frac{3}{2}+15
​2
​
​3
​​ +15 to \frac{33}{2}
​2
​
​33
​​
36x=\frac{33}{2}36x=
​2
​
​33
​​

8 Divide both sides by 3636
x=\frac{\frac{33}{2}}{36}x=
​36
​
​
​2
​
​33
​​
​​

9 Simplify \frac{\frac{33}{2}}{36}
​36
​
​
​2
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​33
​​
​​ to \frac{33}{2\times 36}
​2×36
​
​33
​​
x=\frac{33}{2\times 36}x=
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​33
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10 Simplify 2\times 362×36 to 7272
x=\frac{33}{72}x=
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11 Simplify \frac{33}{72}
​72
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​​ to \frac{11}{24}
​24
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​11
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x=\frac{11}{24}x=
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​
​11
​​
X=11 over 24
4 0
3 years ago
Read 2 more answers
A biking track has a length of 0.8 miles mi. How long is this in feet ft?
Sedbober [7]

Answer:

4224

Step-by-step explanation:

.8 mile = 4224 feet

8 0
3 years ago
Read 2 more answers
if a quadrilateral has two sides that measure 4 inches and angles that all measure 910 degree we can consider the quadrilateral
BartSMP [9]

Answer:

the right answer is rectangle

Step-by-step explanation:

Compare the pairs of sides. One pair measures 4 inches, but the other pair does not and forms 90 ° angles. This figure does not have its four congruent sides, so it is a rectangle.

4 0
3 years ago
Please help n show work
Ivan

Answer: A

Step-by-step explanation:

6 0
4 years ago
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