Total ways = {AAA, AAB, ABA, BAA, ABB, BAB, BBA, BBB}
Ways at least one counter with side A = {AAA, AAB, ABA, BAA, ABB, BAB, BBA}
Hence, the number of ways at least one counter with side A = 7.
Answer:
It's A, Because it makes the most sense in this algebra question.
Step-by-step explanation:
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Answer:$25
20% of 125 is $25 dollars so his commission would be $25
2,000
eighty times twenty five equals two thousand