Algebra 1 , PLEASE PLEASE help . and if you know how to do algebra i'll have more question you can answer .. if you want :, )
2 answers:
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Answer:
Last Option .
Step-by-step explanation:
In this question we will do the factors of given two terms then we will do the common factors of all the terms given in answer to match with.
Common factors of 36h³ = 1×2×2×3×3×h×h×h
Common factors of = 1×2×2×3×h×h×h×h×h×h
In these two terms greatest common factor Of these two terms is = 1×2×2×3×h×h×h = 12h³
Therefore the third term will be the number which has the greatest common factor = 12h³
So the given terms are
6h³ = 1×2×3×h×h×h
12h² = 1×2×2×3×h×h
= 1×2×3×5×h×h×h×h
= 1×2×2×2×2×3×h×h×h×h×h
Therefore the greatest common factor of the term which matches with 12h³ is
The total amount of calories burnt in jogging 2 miles = 185 calories
We have to determine the number of calories burned in jogging 3 miles.
Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.
So, the total amount of calories burnt in jogging 1 mile =
= 92.5 calories
So, the amount of calories burnt in 3 miles =
= 277.5 calories
Therefore, 277.5 calories are burned in jogging 3 miles.