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3 years ago

A triangle has sides measuring 15, 15, and 15 . What are the angle measures of the triangle?

2 answers:

8 0

Since all sides are of the same length, all angles must be of the same magnitude as well.

The sum of the angles of any triangle must equal 180° so we can say:

3α=180 upon dividing both sides by 3 we see:

α=60°

So all of the angles are 60° which is true for all equilateral triangles.

deff fn [24]3 years ago

3 0

The angle measures are 60, 60, 60

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If f(x) = 4x-x², find square root f(3/2)

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Step-by-step explanation:

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1 year ago

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3 years ago

Please help math

Naddika [18.5K]

$\displaystyle\\
15(2a - 2) = 5(a^2 -1) \\ \\ 
30a - 30 = 5a^2-5\\\\
-5a^2 + 30a -30 + 5 =0\\\\
-5a^2 + 30a -25 =0 ~~~~~\Big| \times (-1) \\\\
5a^2 - 30a +25 = 0~~~~~\Big| : 5 \\\\
a^2 - 6a +5 = 0 \\ \\ 
a_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}= \frac{6\pm \sqrt{36-20}}{2}= \frac{6\pm \sqrt{16}}{2}=\frac{6\pm 4}{2}= \boxed{3\pm 2} \\ \\ 
a_1 = 3+ 2 = \boxed{5}\\\\
a_2 = 3-2 = \boxed{1}$

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Step-by-step explanation:

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