All categories

3 years ago

What is the answer to (( 5 x 12)/3)+30-50

Mathematics

2 answers:

SpyIntel [72]3 years ago

8 0

I believe the correct answer is 0

Step-by-step explanation:

To solve this question, we use an abbreviation formula called BODMAS which is:

B = Brackets

O = Of

D = Division

M = Multiplication

A = Addition

S = Subtraction

We solve each element that is available in the order of the abbreviated letter.

1. We solve the brackets:

$(5\times12) = 60$

2. We solve the second bracket:

$(60\div3) = 20$

The equation now is $20+30-50$

3. We now solve addition first:

$20+30=50$

4. Now we solve the subtraction:

$50-50=0$

The answer then = 0

Pavlova-9 [17]3 years ago

8 0

Answer:

The value of given expression is 0.

Step-by-step explanation:

We have to evaluate the given expression:

$\bigg(\displaystyle\frac{(5\times 12)}{3}\bigg)+30-50$

We use the BODMAS rule to evaluate the given expression.

B-Bracket

O-of

D-Division

M-Multiplication

A-Addition

S-Subtraction

$\bigg(\displaystyle\frac{(5\times 12)}{3}\bigg)+30-50\\\\=\bigg(\displaystyle\frac{60}{3}\bigg)+30-50\\\\=20+30-50\\\\=50-50\\\\=0$

The value of expression is 0.

You might be interested in

2. A parking lot holds 40 cars. There are 20 cars in the lot already. Which inequality can be solved to show all the

Pie

C I need to put 20 letters so yea the answer is C

7 0

2 years ago

There are 92 students in a chemistry class. The instructor must choose two students at random. Students in a Chemistry Class Aca

Sergio039 [100]

Answer:

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability that a sophomore non-Chemistry major

Out of 92 students, 9 are non-chemistry major sophomores. So

$P(A) = \frac{9}{92}$

Then a junior non-Chemistry major are chosen at random.

Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

$P(B) = \frac{10}{91}$

What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

$P = P(A)*P(B) = \frac{9}{92}*\frac{10}{91} = \frac{9*10}{92*91} = 0.0108$

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

8 0

3 years ago

GEOMETRY HELP PLEASEEEEEEE!!

Nadya [2.5K]

For number 11 the third angle would be equal X as the second angle is, since the two sides next to the those angles are congruent. Then you would have to set an equation saying that 2x + 38= 180 and then you can just solve for X

3 0

3 years ago

Which equations, tables, or graphs represent functions?

Debora [2.8K]

A represents a function

This is the way

5 0

2 years ago

Use a flowchart to prove if the triangles in each pair of similar. NO LINKS!!!<br>

vekshin1

Answer:

Step-by-step explanation:

Start

<F = <Q Given

<GPF = <RPQ Vertically opposite angles

<FGP = <QRP A triangle has 180 degrees. 2 equal angles means the third pair must be equal

Triangle GPF ~ Triangle RPQ AAA

end

I don't see any way to make these triangles similar except by stating the statement and why it is so. There really are no yes / no choices. If you get another answer, choose it.

JL/LE = 90/27 Given

KL /LD = 90/27 Given

<JLK = <DLK Vertically opposite

Are the ratios equal Yes Then is the angle included Yes

Then the triangles are similar.

Are the ratios not equal No then the triangles cannot be similar

Is the angle not included Then similarity cannot be proved.

ΔJLK ≈ ΔDLK Equal Ratios and included angle === similarity

7 0

2 years ago

Read 2 more answers