C square
E paraellolgram
F trapezoid
A rhombus
B rectangle I can’t see it well
Hope this helps
Multiply the bracket by 6
6(-p+8)= -6p + 12
-6p+48= -6p+12
Move -6p from right side to left side
Sign changes from -6p to +6p
-6p+6p+48= -6p+6p+12
48= 12 ( No solution )
Answer : No solution
Answer:
{42,56,70}
Step-by-step explanation:
a^2 + b^2 = c^2
42^2 = 1764
56^2 = 3136
70^2 = 4900
3136 + 1734 = 4900
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
A=p (1+r)^t
A future value
P present value 4.98
R rate 0.04
T time
After 3 years
A=4.98×(1+0.04)^(3)
A=5.60
7.50=4.98 (1.04)^t
Solve for t
T=log(7.50÷4.98)÷log(1.04)
T=10 years
Hope it helps:-)