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Natasha_Volkova [10]
3 years ago
13

Jason ordered 239,021 pounds of flour to be used in his 25 bakeries . The company

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

So, it says that he ordered 239,021 pounds of flour, but they delivered 451,202 pounds. You are going to subtract the delivered amount to the ordered amount.

451,202 - 239,021 = _________

_________ = The Extra Amount Delivered

451,202 - 239,021 = 212,181

That means, that they had delivered 212,181 extra pounds of flour.

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Help me It’s due tomorrow and I can’t figure it out!!!
yuradex [85]
A.) 30+10=40. So, 90-40=50. Your answer is 50 degrees.
B.) 45+4=49. So, 90-49=41. Your answer is 41 degrees.
C.) 8 to the square root of 2+45=56.31. So, 90-56.31=33.69. Your answer is 33.69 or 33.7 if you need to round. 
D.) One angle is 30 degrees, and another angle is 60 degrees. Your other angle is 90 degrees.
E.) 60+6=66. 90-66=24. Your answer is 24 degrees.
F.) 45+6=51. 90-51=39. Your answer is 39 degrees.
4 0
3 years ago
Solve the equation below:<br> 5x^2 - 55 = 90
Leno4ka [110]
X= √29, -√29

The answer to this question would be ^
3 0
3 years ago
Find the slope of the line through each pair of points. <br> (19, −16), (−7, −15)
erik [133]

Point-Slope:

y+16=-1/26*(x-19)

Finding the regular slope:

m=1/-26=0.03846

7 0
3 years ago
Read 2 more answers
Janelle bought a beach chair on sale at 70% off. The original price was $59.99. Round answers to the nearest cent. a. Find the a
stealth61 [152]

Answer:

A. $41.99

B. $18.00

Step-by-step explanation:

To find discount: 59.99×0.7= 41.99

To find sales price: 59.99-41.99=18

8 0
3 years ago
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

8 0
3 years ago
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