If you do the area (length x width) 24 x 15 it would 360 square ft.
Answer:
Step-by-step explanation:
hello,
the question is not really clear. i believe the intended equation would be
![\sum_{k=1}^{k=n} k^3=\frac{(n(n+1))}{4}](https://tex.z-dn.net/?f=%5Csum_%7Bk%3D1%7D%5E%7Bk%3Dn%7D%20k%5E3%3D%5Cfrac%7B%28n%28n%2B1%29%29%7D%7B4%7D)
please check the attached file for the step by step proof.
Answer: you got the subtracted wrong.
Step-by-step explanation: 115 - 101 = (14)
you said 13
First let t = total # of ribbons
Now if one third of the total ribbons is red, then two thirds of the total ribbons are blue and green ribbons combined.
We are told that the ratio of blue to green ribbons is 2:5... Let b = #of blue ribbons and g = # of green ribbons: then
![\frac{2}{5} = \frac{b}{g}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B5%7D%20%3D%20%20%5Cfrac%7Bb%7D%7Bg%7D%20%20%20)
Or: 2g = 5b and therefore
![b = \frac{2}{5}g](https://tex.z-dn.net/?f=b%20%3D%20%20%5Cfrac%7B2%7D%7B5%7Dg%20%20)
this will be our first equation of the system.
We are also told that there are 162 fewer blue ribbons than green. So it follows that our second equation of the system will be b + 162 = g
Substituting our first equation into the second we get the following:
![\frac{2}{5} g+162=g](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B5%7D%20%20g%2B162%3Dg)
Solving this equation, we find g = 270
Now g = 270 implies that: b + 162 = 270 and b = 108
Also the sum of blue ribbons and green ribbons is now 378 which is
![\frac{2}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20)
of the total number of ribbons.
Thus,
![\frac{2}{3} t=378](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20t%3D378)
and solving we find t = 567
Let me know if you have any questions... this is just how I saw the problem..there may be a more eloquent ways to solve
Answer:
121 books
Step-by-step explanation:
bc that equals 11 so there are 11 squares plus the two missing ones from before so u do 11x11 which would be 121
hope this helps :>