<span>3y = x + 6
y – x = 3 -----------> x=y - 3 (substitute in 1st equation)
3y = y - 3 +6
3y - y = 3
2y = 3
y = 2/3
x= y - 3 = 2/3 -3 = 2/3 - 9/3 = - 7/3
</span>x= - 7/3, y = 2/3<span>
</span>
a) C(0.5) = 39, C(2) = 39, C(4) = 69
b) Answers in part (a) represents the values of C at x = x₀
c) C(x) is continuous at x = 2
C (x) = 39 for 0 ⩽ x ⩽ 2
Since x = 0.5 is in the range 0 ⩽ x ⩽ 2:
C(0.5) = 39
Since x = 2 is in the range 0 ⩽ x ⩽ 2
C(2) = 39
Since x = 4 is in the range x > 2
C(4) = 39 + 15(x - 2)
C(4) = 39 + 15 (4 - 2)
C(4) = 39 + 15(2)
C(4) = 39 + 30
C(4) = 69
b) The answers in part A represents C(x). That is, the values of C at x = x₀
c) Is C(x) continuous at x = 2
C(2) = 39

Since
, the function C(x) is continuous at x = 2
Learn more here: brainly.com/question/20710468
Answer:
Directrix
Step-by-step explanation:
4x - 2 = 2x + 8
2x -2 = 8
2x = 10
x = 5
4(5)-2 = 2(5)+8
20-2 = 10+8
18 = 18
Answer:
(7,6)
Step-by-step explanation: