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3 years ago

3.

Mathematics

2 answers:

FrozenT [24]3 years ago

6 0

Answer:

3: 3 x ( 3 x + 5 ) or B

4: 10 m ( 2 n − 3 ) or B

5: 4 x y ( 2 x y − x − 3 ) or D

konstantin123 [22]3 years ago

4 0

For number three you would take out a 3 and an X

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3 years ago

How to find point form of (-5,4) and (5,1)

Sphinxa [80]

The point slope form of (-5, 4) and (5, 1) is $y-4=\frac{-3}{5}(x+5)$

<u>Solution:</u>

Given that a line is passing through points (-5,4) and (5,1)

We need to determine point slope form of line

Equation of line passing through point $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$ is given as:

$\mathrm{y}-\mathrm{y}_{1}=\frac{\left(\mathrm{y}_{2}-\mathrm{y}_{1}\right)}{\left(\mathrm{x}_{2}-\mathrm{x}_{1}\right)}\left(\mathrm{x}-\mathrm{x}_{1}\right)$

$\text { In our case } x_{1}=-5, y_{1}=4, x_{2}=5, y_{2}=1$

Substituting given value in (1) we get

$\begin{array}{l}{y-4=\frac{(1-4)}{(5-(-5))}(x-(-5))} \\\\ {=>y-4=\frac{-3}{10}(x-(-5))} \\\\ {=>y-4=\frac{-3}{5}(x+5)}\end{array}$

Hence the point slope form of line is $y-4=\frac{-3}{5}(x+5)$

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4 years ago