Answer:
6 tickets were purchased at $47
8 tickets were purchased at $57
Step-by-step explanation:
Let the tickets purchased at $47 be x
Let the tickets purchased at $57 be y
We can form an equation from the question given which will be:
x + y = 14 ....... i
47x + 57y = 738 ........ ii
From equation i
x = 14 - y ........ iii
Substitute iii into ii
47x + 57y = 738
47(14-y) + 57y = 738
658 - 47y + 57y = 738
Collect like terms
-47y + 57y = 738 - 658
10y = 80
y = 80/10
y = 8
8 tickets were purchased at $57
Note that from i
x + y = 14
x + 8 = 14
x = 14 - 8
x = 6
6 tickets were purchased at $47
Answer:25 is the answer
Step-by-step explanation:
Answer:
Original number = 38
Step-by-step explanation:
10*x + y
x = y - 5
10y + x = 2 (10x + y) + 7
10y + y - 5 = 2(10(y - 5) + y) + 7
11y - 5 = 2(10y - 50 + y ) + 7
11y - 5 = 2(11y - 50) + 7
11y - 5 = 22y - 100 + 7
11y - 5 = 22y - 93
11y + 88 = 22y
88 = 11y
y = 8
x = y - 5
x = 8 - 5
x = 3
So the original number is 38. Does that work?
3 is 5 less than 8.
83 = 2*38 + 7
83 = 76 + 7
83 = 83. Yes it works.
Answer:
the answer is 30
............................
Number of weekend minutes used: x
Number of weekday minutes used: y
This month Nick was billed for 643 minutes:
(1) x+y=643
The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44
We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44
Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y
Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44
Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72
Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243
Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400
Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
