Work out the length of line segment PQ.

1 answer:

6 0

The length is:

the square root of [ (the difference in 'x' values)² + (the difference in 'y' values)² ]

D = √ [ (-2-6)² + (5-2)² ]

= √ [ (-8)² + (3)² ]

= √ (64 + 9) = √75 = 5√3 = 8.66 (rounded to 3 sig-figs)

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The diameters of Douglas firs grown at a Christmas Tree Farm are normally distributed with a mean of 4 inches and a standard dev

leva [86]

Answer:

The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.

Step-by-step explanation:

In this problem we have a normal ditribution with mean of 4.0 in and standard deviation of 1.5 in.

The proportion of the trees that are expected to have diameters greater than 5 inches is equal to the probability of having a tree greater than 5 inches.

We can calculate the z value for x=5 in and then look up in a standard normal distribution table the probability of z.

$z=\frac{x-\mu}{\sigma}=\frac{5-4}{1.5}=0.67$