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agasfer [191]
3 years ago
6

A 10 Newton effort force is required to lift a 10 kg box just off the ground. What is the effort required to lift the box off th

e ground using a 3m long lever? [The fulcrum is placed 0.5m from the box.]
Physics
2 answers:
Zanzabum3 years ago
6 0

Answer:

effort required to  lift the box off the ground using a 3m long lever=2N

Explanation:

In this question we have given

force required,F=10N

mass of box.m=10kg

length of lever, l=3m

distance between fulcrum and box,d=.5m

effort required to  lift the box off the ground using a 3m long lever=?

Here,

Effort required to  lift the box off the ground using a 3m long lever \times (3m-0.5m) =F \times 0.5m

Effort required to  lift the box off the ground using a 3m long lever \times (3m-0.5m) =10N \times 0.5m

Effort=\frac{10\times 0.5}{3-0.5}

Effort=2N

Karo-lina-s [1.5K]3 years ago
5 0

2.0 N is the answer, I hope this helps :D




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3 years ago
A 81 kg person sits on a 3.8 kg chair. Each leg of the chair makes contact with the floor in a circle that is 1.2 cm in diameter
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Answer:

1.9 MPa

Explanation:

Mass of person = 81 kg

Mass of chair = 3.8 kg

Diameter of contact point = 1.2 cm = D

Radius of contact point = 1.2/2 = 0.6 cm

Total mass of chair and person = 81 + 3.8 = 84.8 kg = M

Acceleration due to gravity = 9.81 m/s²

Force acting on the floor

<em>F = Mg</em>

<em>⇒F = 84.8×9.81</em>

<em>⇒F = 831.888 N</em>

Area of the contact point

<em>A = πR²</em>

<em>⇒A = π0.006²</em>

<em>⇒A = π0.000036 m²</em>

Area of the four points is

<em>4A = 0.000144π m²</em>

Pressure

p=\frac{F}{A}\\\Rightarrow p=\frac{831.888}{0.000144\pi}\\\Rightarrow p=1838876.21\ Pa=1.83887621\times 10^6\ Pa=1.9 MPa

Pressure exerted on the floor by each leg of the chair is 1.9 MPa

5 0
3 years ago
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Answer:

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Explanation:

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Generally the equation for momentum is mathematically given by

P=mv

Therefore

T-Joe momentum P_J

P_J=65*3

P_J=195N

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