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agasfer [191]
4 years ago
6

A 10 Newton effort force is required to lift a 10 kg box just off the ground. What is the effort required to lift the box off th

e ground using a 3m long lever? [The fulcrum is placed 0.5m from the box.]
Physics
2 answers:
Zanzabum4 years ago
6 0

Answer:

effort required to  lift the box off the ground using a 3m long lever=2N

Explanation:

In this question we have given

force required,F=10N

mass of box.m=10kg

length of lever, l=3m

distance between fulcrum and box,d=.5m

effort required to  lift the box off the ground using a 3m long lever=?

Here,

Effort required to  lift the box off the ground using a 3m long lever \times (3m-0.5m) =F \times 0.5m

Effort required to  lift the box off the ground using a 3m long lever \times (3m-0.5m) =10N \times 0.5m

Effort=\frac{10\times 0.5}{3-0.5}

Effort=2N

Karo-lina-s [1.5K]4 years ago
5 0

2.0 N is the answer, I hope this helps :D




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3 years ago
1.) if the total momentum for a system is the same before and after the collision, we say that momentum is conserved. if momentu
gogolik [260]

From the law of the conservation of energy;  the ratio of the total kinetic energy after the collision to the total kinetic energy before the collision must be 1.

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6 0
2 years ago
I know that the PE will be the same for all the objects, but other then that I'm confused on what is correct and what isn't. ​
joja [24]

Answer:

Neither aspects of Dominique are correct.

Explanation:

They will not have the same speed before hitting the ground.

The block C has an initial horizontal velocity v₀ₓ , therefore the total ultimate speed before hitting the ground is  v = √ v₀ₓ² + vy²

It didn't matter how the blocks were dropped, they all landed at the same time. If any block has an initial vertical velocity it will have a higher end velocity. If Dominique means dropped from the rest then the previous claim is true. It is important how they were dropped.

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God is with you!!!

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3 years ago
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acceleration of car is 1.8 m/s^2

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7 0
3 years ago
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