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agasfer [191]
3 years ago
6

A 10 Newton effort force is required to lift a 10 kg box just off the ground. What is the effort required to lift the box off th

e ground using a 3m long lever? [The fulcrum is placed 0.5m from the box.]
Physics
2 answers:
Zanzabum3 years ago
6 0

Answer:

effort required to  lift the box off the ground using a 3m long lever=2N

Explanation:

In this question we have given

force required,F=10N

mass of box.m=10kg

length of lever, l=3m

distance between fulcrum and box,d=.5m

effort required to  lift the box off the ground using a 3m long lever=?

Here,

Effort required to  lift the box off the ground using a 3m long lever \times (3m-0.5m) =F \times 0.5m

Effort required to  lift the box off the ground using a 3m long lever \times (3m-0.5m) =10N \times 0.5m

Effort=\frac{10\times 0.5}{3-0.5}

Effort=2N

Karo-lina-s [1.5K]3 years ago
5 0

2.0 N is the answer, I hope this helps :D




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A straight wire of length 0.56 m carries a conventional current of 0.4 amperes. What is the magnitude of the magnetic field made
djverab [1.8K]

Answer:

The magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.

Explanation:

Given;

length of the straight wire, L = 0.56 m

conventional current, I = 0.4 A

distance of magnetic field from the wire, r = 2.6 cm = 0.026 m

To determine magnitude of magnetic field made by current in the wire, we will apply Bio-Savart Law;

B = \frac{\mu_o}{4\pi r} \frac{LI}{\sqrt{r^2 +(L/2)^2} } \\\\B = \frac{4\pi *10^{-7}}{4\pi *0.026} \frac{0.56*0.4}{\sqrt{(0.026)^2 +(0.56/2)^2} }\\\\B = 3.846*10^{-6}(0.7966)\\\\B = 3.064*10^{-6} \ T

Therefore, the magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.

3 0
3 years ago
The medium through which a mechanical wave passes can be a solid, liquid, or gas. Properties of a wave change when it moves from
Tpy6a [65]

Answer:

Option A

Explanation:

Mechanical waves requires some medium to travel through. They travel faster in the dense medium as compared to a free medium.

The speed of a mechanical wave is fastest in the solid medium and the slowest in the gaseous medium. Hence, as the wave traverses from gaseous medium to the solid medium, its speed increases.

Thus, option A is correct

3 0
3 years ago
Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of
emmainna [20.7K]

Answer:

5,2

Explanation:

From the question we are told that:

Speed of light C=3.0×10^8 m/s.

Generally the equation for Average Speed is mathematically given by

V_{avg}=\frac{d}{t}

Where

d=Distance between the Earth and the sun

d=1.5*10^11m

Therefore

t=\frac{d}{V_{avg}}

t=\frac{1.5*10^11m}{3.0×10^8 m/s.}

t=5*10^2s

Since m and n is given in the form of

m*10^n

Therefore

m=5 & n=2

5,2

3 0
3 years ago
U need help so can some one help me
GrogVix [38]

Answer:

are sure this is a question

7 0
2 years ago
A woman is standing in the ocean, and she notices that after a wave crest passes, five more crests pass in a time of 54.0 s. The
timama [110]

Answer:

a) f=0.1 Hz ; b) T=10s

c)λ= 36m

d)v=3.6m/s

e)amplitude, cannot be determined

Explanation:

Complete question is:

Determine, if possible, the wave's (a) frequency, (b) period, (c) wavelength, (d) speed, and (e) amplitude.

Given:

number of wave crests 'n'= 5

pass in a time't' 54.0s

distance between two successive crests 'd'= 36m

a) Frequency of the waves 'f' can be determined by dividing number of wave crests with time, so we have

f=n/t

f= 5/ 54 => 0.1Hz

b)The time period of wave 'T' is the reciprocal of the frequency

therefore,

T=1/f

T=1/0.1

T=10 sec.

c)wavelength'λ' is the distance between two successive crests i.e 36m

Therefore, λ= 36m

d) speed of the wave 'v' can be determined by the product of frequency and wavelength

v= fλ => 0.1 x 36

v=3.6m/s

e) For amplitude, no data is given in this question. So, it cannot be determined.

5 0
3 years ago
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