Question

A Porter carries a 25 kg suitcase a distance of 1 km. Explain why the Porter does no work

Answer 1

The Porter does no work because the force applied is perpendicular to the displacement

Explanation:

The work done by a force applied to an object is given by:

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and the displacement of the object

From the formula, we notice that:

- The work done is maximum when the force is parallel to the displacement (because $\theta = 0^{\circ}, cos 0^{\circ}=1$)

- The work done is zero when the force is perpendicular to the displacement (because $\theta = 90^{\circ}, cos 90^{\circ}=0$)

In this problem, Porter is carrying the suitcase: this means that the force he is applying is upward (to balance the weight of the suitcase, pulling down), while the displacement is in the horizontal direction: therefore, force and displacement are perpendicular, so the work done is zero.

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