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miv72 [106K]
3 years ago
10

What additional information would you need to prove that ΔABC ≅ ΔDEF by SAS?

Mathematics
2 answers:
Marina86 [1]3 years ago
8 0
D.segment bc segment ef
quester [9]3 years ago
7 0

Answer: d. d. segment BC ≅ segment EF

Step-by-step explanation:

The SAS Postulate says that if two sides and the included angle of one triangle are congruent to the corresponding two sides and the included angle of another triangle, then the triangles are said to be congruent.

In the given figure , we have two triangles ΔABC and ΔDEF in which

∠B≅∠E

segment AB ≅segment ED.

According to the SAS postulate, the additional information would be needed to prove that ΔABC ≅ ΔDEF will be : segment BC ≅ segment EF

∵ ∠B is the included angle between segment BC and segment AB and ∠E is the included angle between segment EF and segment ED.

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Need help please help me
ANTONII [103]
Megan:
x to the one third power =  x ^{1/3}
<span>x to the one twelfth power = </span>x ^{1/12}

<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>\frac{x ^{1/3}}{x ^{1/12}}
<span>
Since </span>\frac{ x^{a} }{ x^{b} } = x ^{a-b}
then \frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}


Julie:
x times x to the second times x to the fifth = x * x² * x⁵

<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>\sqrt[32]{x* x^{2} * x^{5} }
<span>
Since </span>x^{a}* x^{b}= x^{a+b}
Then \sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }

Since \sqrt[n]{x^{m}} = x^{m/n} }
Then \sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.
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