Answer:
122.88
Step-by-step explanation:
<u>3072</u>
25
122.88 sorry I forgot how to show all the work I love my calculator but hopefully the answer you need will help.
Answer:
<em>The monthly payment is $450.71</em>
Step-by-step explanation:
<u>Financial Computing
</u>
Given the loan amount A, the loan term t, and the APR (annual percentage rate), the montly payment is computed as

where f is

The provided data is



Since the payments will be made monthly, the values of n and i are:


Calculating f:



Now for the payments:


Answer:
C. Each Sandwich has 1/4 pounds of ham
Step-by-step explanation:
The characteristic solution follows from solving the characteristic equation,

so that

A guess for the particular solution may be

, but this is already contained within the characteristic solution. We require a set of linearly independent solutions, so we can look to

which has second derivative

Substituting into the ODE, you have



Therefore the particular solution is

Note that you could have made a more precise guess of

but, of course, any solution of the form

is already accounted for within

.