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4 years ago

Tommy is 23 years younger than his father. together their ages total up to 45 years. howl old are Tommy and his father?

1 answer:

7 0

The answer is 45 total.

So Tommy is 22 years old while his Father is 45.

45 years of age total, tommy is 23 years younger so 45 - 23 = 22 so tommy is 22 while his father is 45.

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3^(x−1) = 27<br> I need the answer please and thanks

bogdanovich [222]

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4 years ago

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Sav [38]

Answer: x = 45

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2 years ago

3x + 8y = 28<br> 3x + 2y = 4<br> Find both the x and y coordinates

umka2103 [35]

Answer:

(- $\frac{4}{3}$ , 4 )

Step-by-step explanation:

Given the 2 equations

3x + 8y = 28 → (1)

3x + 2y = 4 → (2)

Subtracting (2) from (1) term by term will eliminate the x- term

(3x - 3x) + (8y - 2y) = (28 - 4), that is

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y = 4

Substitute y = 4 into either of the 2 equations and solve for x

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x = - $\frac{4}{3}$

Solution is (- $\frac{4}{3}$ , 4 )

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3 years ago

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In how many ways can a person enter a room that has three doors and leave it by (a) a different door? (b) any door? How do i do

White raven [17]

Part (a)

Label the doors A, B, C.

If a person goes through door A, then they have 2 choices (B or C) to pick as an exit. Similarly, if they go through door B, then they have 2 choices for an exit (A or C). Finally, if they go through door C, then they have 2 choices for an exit (A or B).

We have 3 choices for the entrance, and 2 choices for the exit.

So overall, 3*2 = 6 different combinations are possible.

Those 6 combos are

AB, AC, BA, BC, CA, CB

<h3>Answer: 6</h3>

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Part (b)

This is effectively the same as part (a), but we can now re-use the entrance door. For any door we enter, we have 3 choices to pick from for the exit. There are 3 doors, so 3 entrances and 3 exits, meaning 3*3 = 9 different combinations.

Those 9 combos are

AA, AB, AC, BA, BB, BC, CA, CB, CC

<h3>Answer: 9</h3>

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3 years ago

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hoa [83]

I did it for you in the picture!

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4 years ago