All the triangles are similar, so the ratio of (long leg)/(short leg) is the same. The long leg of ΔADB is
.. AD = AC -DC = 20 -4
.. AD = 16
Then
.. (long leg)/(short leg) = AD/DB = BD/DC
.. 16/h = h/4
.. h^2 = 64
.. h = 8
Selection D is appropriate.
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You may see this again. The altitude (h) from the right angle in a right triangle is the geometric mean of segments AD and DC. That is,
.. h = √((AD)*(DC))
Answer:
105
For the 4 triangular faces, find the area with 1/2 × base × height = 1/2 × 5 × 8 = 20
4 triangles -> 20 × 4 = 80
The area of the square base is 25
80 + 25 - 105 
Answer:
x³ - 3x² - 9x + 27
= x²(x - 3) - 9(x - 3)
= (x² - 9)(x - 3)
= (x -3)(x + 3)(x - 3)
= (x + 3)(x - 3)²
Step-by-step explanation:
Answer:
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then send me
First off, you really don't need to write "what percent???" here.
25% of 80 is 0.25(80) = 20.