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alexandr1967 [171]
3 years ago
12

Find all real values of $v$ that satisfy the equation $(v+6)^2 = 324$. If you find more than one, then list your values in incre

asing order, separated by commas.
Mathematics
2 answers:
Karolina [17]3 years ago
8 0
We have that

(v+6)^2 = 324-----> I raise to 1/2 both members----> [(v+6)^2]^(1/2)=(324)^(1/2)[(v+6)]=(324)^(1/2)-------------> v+6=√324
v=√324-6---------> 18-6=12
v=12

the answer is v=12
Olenka [21]3 years ago
6 0

Answer:

The values of v in increasing order are, -24, 12

Step-by-step explanation:

Given equation is,

(v+6)^2=324

v+6=\pm 18

v=-6\pm 18

\implies v=-6-18\text{ or }v=-6+18

\implies v = -24\text{ or }v=12

Since, -24 < 12

Thus, the values of v in increasing order are,

-24, 12

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Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

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\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

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\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

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The value B is 7. If we apply B=7 the answer is 17 for the expression 17×\frac{b}{7}

Step-by-step explanation:

            The given expression is 17×\frac{b}{7}  

Step:1

            Form an equation from given data,

            17×\frac{b}{7}= 17..............................(1)

                                                         (∵ product equal to 17)

Step:2

            Check for alternatives by apply the value of B in eqn (1)

            Assume be value of B for check the equation

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            Take, B=3,

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