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3 years ago

I will give brainiest to whoever answers correctly !!

Mathematics

1 answer:

Lena [83]3 years ago

3 0

Answer: the mark up price of the fish dinner is around 36.36%

Explanation: 18.75 - 13.75/13.75=5
5 divided by 13.75= 0.36363636.

Hope this helps!

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Solve S = 2πrh for r

Elodia [21]

Divide both sides by 2<span>πh:-

r = S / 2</span><span>πh Answer</span>

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3 years ago

You want to purchase a pair of shoes for at least $150. You have $55 so far. You earn $10.00 per hour at your job write an inequ

VikaD [51]

55+10.00x ≥ 150 x ≥ 9.5 hours I hope that helps

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3 years ago

There is a closed carton of eggs in Mai's refrigerator. The carton contains e eggs and it can hold 12 eggs.

lakkis [162]

Answer:

the inequality means there is less than 12 eggs

Step-by-step explanation:

" e eggs" is < 12

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2 years ago

You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an

navik [9.2K]

Answer:

1) yes ; 2) 1/36 ; 3) 1/36 ; 4) 1/18

Step-by-step explanation:

Given the following :

Two fair dice : 1 green ; 1 red

A) Are the outcomes on the dice independent:

Yes, becomes the outcome of the green dice does not have any effect on the outcome of the red dice.

B) Find P(1 on green die and 5 on red die).

Probability = (number of required outcome) / (total possible outcomes)

Total outcomes of a dice = 6

P(1 on green) = 1 / 6

P(5 on red) = 1/6

P(1 on green die and 5 on red die) :

(1/ 6) × (1/6) = 1/36

C) Find P(5 on green die and 1 on red die)

P(5 on green) = 1/6

P(1 on red) = 1/6

Find P(5 on green die and 1 on red die):

1/6 × 1/6 = 1/36

D) Find P((1 on green die and 5 on red die) or (5 on green die and 1 on red die))

P(5 on green die and 1 on red die) = 1/36

P(1 on green die and 5 on red die) = 1/36

P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) =

P(5 on green die and 1 on red die) + P(1 on green die and 5 on red die)

= (1/36 + 1/36) = 2 /36 = 1/18

8 0

3 years ago

Use the multiplication property of exponents to determine if each statement is true or false.

lisabon 2012 [21]

1)
LHS:
${a}^{4} \times {a}^{3} \times a \\ = {a}^{4 + 3 + 1} \\ = {a}^{7}$
LHS = RHS. So, the statement is true

2)
LHS:
${5}^{2} \times {3}^{4} \\ = 25 \times 81 \\ = {5}^{2} \times {9}^{2} \\ = {45}^{2}$
LHS not equal to RHS. So, the statement is false

3)
LHS:
${x}^{6} \times {x}^{0} \times {x}^{2} \times {x}^{3} \\ = {x}^{6 + 0 + 2 + 3} \\ = {x}^{11}$
LHS = RHS. So, the statement is true.

4)
LHS:
$7 {m}^{2} \times 2m \times 4 {m}^{5} \\ = (7 \times 2 \times 4) {m}^{2 + 1 + 5} \\ = 56 {m}^{8}$
LHS = RHS. So, the statement is true.

7 0

3 years ago