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madreJ [45]
3 years ago
9

Plllzzz answer neeeeed heeelp will be brainliest

Mathematics
2 answers:
Licemer1 [7]3 years ago
4 0

Answer:

20 miles in 2 hours

Step-by-step explanation:

Since the x-axis is the hours, we know that 2 would mean two hours, and since the y-axis is distance, we know that  Travis has travled 20 miles.

Firlakuza [10]3 years ago
3 0
The coordinate (2,20) indicates that he rode 20 miles in 2 hours
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An SRS of 450 450 high school seniors gained an average of ¯ x = 20 x¯=20 points in their second attempt at the SAT Mathematics
maria [59]

Answer: (15.47, 24.53)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :_

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where n= sample size.

\sigma = standard deviation.

\overline{x}= sample mean.

z*= Critical value.

Given : n= 450

\overline{x}=20

\sigma=49

Critical value for 95% confidence = z*=1.96     [From z-value table]

Then, the 95% confidence interval will be :-

20\pm (1.96)\dfrac{49}{\sqrt{450}}

\approx 20\pm (1.96)(2.31)

\approx 20\pm 4.53

=(20-4.53,\ 20+4.53)=(15.47,\ 24.53)

Hence, the 95% confidence interval for the mean change in score μ μ in the population of all high school seniors. : (15.47, 24.53)

3 0
3 years ago
Assume that a random sample of 4 Goldfinch birds are going to be used to test the above hypothesis. Compute the largest value of
Misha Larkins [42]

This question is incomplete, the complete question is;

Assume that body masses of Goldfinch birds follow a normal distribution, with a standard deviation equal to 0.04 oz. An ornithologist who would like to make some inference about the average body mass of the Goldfinch birds. In particular, at a significance level of 0.01, she would like to test the null hypothesis H₀: Average body mass of the Goldfinch birds is 0.5 oz, against the alternative claim that average body size is less than 0.5 oz.

      Assume that a random sample of 4 Goldfinch birds are going to be used to test the above hypothesis. Compute the largest value of the sample mean, that will allow the experimenter reject the null and prove the alternative at significance level 0.01. For this problem, make sure that your solution includes all steps of your computation. You will not earn points if you just use a formula

Answer: the largest value of the sample mean that will enable the experimenter to reject the null hypothesis is 0.4534 oz.

Step-by-step explanation:

Let us consider testing a hypothesis about a population mean with population standard deviation that is known,

Let the average body mass of the Goldfinch bird be μ^μ

Now our hypotheses are will be;

H₀ : μ = 0.5    and

H₁ : μ < 0.5

For the test, we shall use the z statistic which will be

z = (x"-μ)/(σ/√n)

Now given that;

σ = 0.04 and n = 4  

sample mean x" = ?

Now in order to be able to reject the null hypothesis, the p-value should be ≤ α = 0.01.

so to find the largest value of sample mean, we will use the maximum of p-value that is 0.01.

For a p-value = 0.01 at the lower tail (which is the percentile for z),

the corresponding z will be -2.33

so we substitute our values into our formula

z = (x"-μ)/(σ/√n)

z(σ/√n) = (x"-μ)

-2.33(0.04/√n) = (x"-0.5)

-0.0466 = x" - 0.5

x" = 0.5 - 0.0466

x"= 0.4534

therefore the largest value of the sample mean that will enable the experimenter to reject the null hypothesis is 0.4534 oz.

4 0
3 years ago
Is -3 greater than 4 <br> please answer quit
Aneli [31]

Answer:

No

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Plz help me well mark brainliest!!
gregori [183]

Answer:

x=-52

1/3x-2/3=-18

multiply both sides by 3

x-2=-54

x=-54+2

x=-52

4 0
3 years ago
Read 2 more answers
What is 485 times 34
Svet_ta [14]
The answer is sixteen thousand four hundred ninety
4 0
3 years ago
Read 2 more answers
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