Question

A house has 3 rectangular countertops. Each countertop is 4 3/8 by 2 2/5 feet. How many square feet of tile is needed to cover all of the countertops?

Answer 1

Answer:

$31\frac{1}{2}ft^2$

Step-by-step explanation:

From the information given each of the three rectangular countertops has dimension $4\frac{3}{8}$ by  $2\frac{2}{5}$ feet.

The area of a rectangular shapes is the product of the dimensions.

Each rectangular countertop has area;

$4\frac{3}{8}\times 2\frac{2}{5}=\frac{35}{8}\times \frac{12}{5} =10\frac{1}{2}ft^2$

Therefore the number of square feet tiles needed to cover all the countertops is $=3\times 10\frac{1}{2}=31\frac{1}{2}ft^2$