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kolezko [41]
2 years ago
10

The frequency with which a cricket chirps varies directly with the temperature. If the cricket chirps 100 times per minute in 80

° weather, it will chirp how many times per minute in 92° weather?
A) 87
B) 90
C) 95
D) 115
Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
3 0

The answer is: D) 115

The explanation is shown below:

1. You have that the frequency with which a cricket chirps varies directly with the temperature, which you can express it as following:

y=kx

Where y is the frequency with which a cricket chirps, x is the temperature and k is the constant of proportionality.

2.  If the cricket chirps 100 times per minute in 80° weather, you can calculate k as below:

k=\frac{100}{80}=1.25

3. Therefore, the frequency in 92° weather is:

y=1.25x\\y=(1.25)(92)\\y=115

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7700÷623 with answer and remainder
Free_Kalibri [48]
7700/623
= 623*12 + 224

Therefore, the answer is 12 and the remainder is 224.

Hope this helps !

Photon
3 0
3 years ago
Read 2 more answers
Q5 Q6.) Find the exact value of the six trigonometric functions of theta.
lilavasa [31]
5y - 2x + 1 = 0.
5y = 2x-1.

y = 2/5 x - 2/5

this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)


tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2



5 0
3 years ago
Read 2 more answers
Which expression represents the distance between 1.8 and 9.4 on the number line?
zhuklara [117]

Answer:

|9.4-1.8|

Step-by-step explanation:

To find distance, you take the largest value minus the smallest value and then take the absolute value of that because distance can't be negative.

7 0
3 years ago
Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
23 kg of potatoes cost $138. How much would 7 kg cost? lol i haven't done this in a while and there just now telling us to do it
Aleonysh [2.5K]

Answer:

$42

Step-by-step explanation:

138/23 = $6 per kg

6*7 = 42

8 0
3 years ago
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