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3 years ago

BEN ELİF81 BU HESABI TAKİP EDERMİSİN EĞER BENİ TAKİP EDERSENİZ BEN DE SİZİ TAKİP EDERİM.

Mathematics

1 answer:

FrozenT [24]3 years ago

8 0

256363 okay i don’t know just try okay

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A point is randomly chosen on a map of North America. Describe the probability of the point being in each location: North Americ

Aleks04 [339]

Answer:

We know that the map is of North America:

The probabilities are:

1) North America:

As the map is a map of North America, you can point at any part of the map and you will be pointing at North America, so the probability is p = 1

or 100% in percentage form.

2) New York City.

Here we can think this as:

The map of North America is an extension of area, and New Yorck City has a given area.

As larger is the area of the city, more probable to being randomly choosen, so to find the exact probability we need to find the quotient between the area of New York City and the total area of North America:

New York City = 730km^2

North America = 24,709,000 km^2

So the probability of randomly pointing at New York City is:

P = ( 730km^2)/(24,709,000 km^2) = 3x10^-5 or 0.003%

3) Europe:

As this is a map of Noth America, you can not randomly point at Europe in it (Europe is other continent).

So the probaility is 0 or 0%.

5 0

3 years ago

Find the better buy plz quick

Nana76 [90]

It's letter c 89 cents

4 0

3 years ago

Read 2 more answers

1/2 (x-1) - 1/4 (3-x) =2

ololo11 [35]

1(x-1)/2-1(3-X)/4=2/1. X-1/2-3+x/4=2/1. Find common denominator. 2x-2-3+x=8. 2x+x-5=8 3x=8+5. X=13/3.

4 0

3 years ago

Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p

PIT_PIT [208]

Answer:

Colin has 8 sheets left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = $x$

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

$\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)$

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

$\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)$

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

$\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8$

So, the answer is:

Colin has 8 sheets left for his third class.

5 0

3 years ago

Multiply. assume that no denominator equals zero x^2-16

lawyer [7]

There's nothing to multiply. However, you can factor it to get (x + 4)(x - 4).

4 0

3 years ago